<h2>
Answer:</h2>
a)
The probability that both televisions work is: 0.42
b)
The probability at least one of the two televisions does not work is:
0.5833
<h2>
Step-by-step explanation:</h2>
There are a total of 9 televisions.
It is given that:
Three of the televisions are defective.
This means that the number of televisions which are non-defective are:
9-3=6
a)
The probability that both televisions work is calculated by:

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.
and the total outcome is the selection of 2 televisions from a total of 9 televisions)
Hence, we get:

b)
The probability at least one of the two televisions does not work:
Is equal to the probability that one does not work+probability both do not work.
Probability one does not work is calculated by:

and the probability both do not work is:

Hence, Probability that atleast does not work is:
0.5+0.0833=0.5833
9r - 6 = 8r + 3
r = 9
EF = 4r + 19 = 4(9) + 19 = 36 + 19 = 55
hope it helps
I'll go out on a limb and suppose you're given the matrix

and you're asked to find the determinant of

, where

and given that

.
There are two properties of the determinant that come into play here:
(1) Whenever a single row/column is scaled by a constant

, then the determinant of the matrix is scaled by that same constant;
(2) Adding/subtracting rows does not change the value of the determinant.
Taken together, we have that
Answer:
Step-by-step explanation:
if (x,y) is the centroid. Then x=(x1+x2+x3)/3,y=(y1+y2+y3)/3
5.
x=(-2+4+10)/3=4
y=(6+0+6)/3=4
centroid=(4,4)
6.
x=(3+5-2)/3=2
y=(3-1+1)/3=1
centroid=(2,1)