Step-by-step explanation:
the number of pupils are in the lower school
= (1- 1/5 - ¼) × 600
= (20/20 - 4/20 - 5/20)×600
= (11/20) ×600
= 330 pupils
Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
Answer:
Step-by-step explanation:
(200+30+5)(40+9)
40*200 = 8000
40*30= 1200
40*5=200
9*200= 1800
9*30=270
9*5=45
8000+1200+200+1800+270+45 =11515
Answer:
x = -2
Step-by-step explanation:
1) add 2 to both sides to eliminate -2.
5x = -10
2) divide both sides by 5.
x = -2
Answer:
C
Step-by-step explanation:
It is the only answer where the negative signs do not even out on both sides of the equation.
