Let speed of the boat in still water = x miles per hour
Let speed of the current = y miles per hour
When water and current both flow in same direction then effective speed will be sum of both speeds that is (x+y)
now plug the given values in formula speed=distance/time
we get equation:
(x+y)=160/8
or x+y=20...(i)
When water and current both flow in opposite direction then effective speed will be difference of both speeds that is (x-y)
now plug the given values in formula speed=distance/time
we get equation:
(x-y)=160/40
or x-y=4
or x=4+y...(ii)
plug value of x into (i)
4+y+y=20
4+2y=20
2y=16
y=8
plug value of y into (ii)
x=4+8=12
Hence final answer is given by:
Speed of the boat in still water = 12 miles per hour
Speed of the current = 8 miles per hour
Answer:
653.84 lbs.
Step-by-step explanation:
To make the computation simple, assume the 450 lb force acts along the x axis in the positive direction.
The x component of the 300 lb force is 300cos(60)=150 lbs.
The y component of the 300 lb force is 300sin(60)=
lbs.
The x component of the total force is the sum of the x components of the two forces.
Fx=150+450=600
Fy=259.81
The net force is obtained using the Pythagorean theorem, since the two force components are perpindicular.
F=Sqrt(Fx^2+Fy^2)=Sqrt(360000+67501.24)=Sqrt(427501)=653.84 lbs.
Just trying to win the CONTEST BUT GOOOOD LUCK
Let's use our trigonometric skills to solve for this one:
ANSWER:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(−2,−16)
Equation Form:
x= −2, y= −16
