Someone plzzz help me i suck at math!!!
1 answer:
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Answer:
sqrt 58
Step-by-step explanation:
7^2+3^2=c^2
c=
So,
For number one, there will be an infinite number of solutions, as there are two placeholders.
3x - 2y = 6
It seems we can use the intercept method.
3x - 2(0) = 6
3x = 6
Divide both sides by 3
x = 2
This is one solution: (2,0)
3(0) - 2y = 6
-2y = 6
Divide both sidees by -2
y = -3
This is another solution: (0,-3)
You should now be able to draw the line.
If you want intercept form for this equation, just manipulate the equation in order to get the y = mx + b form.
Subtract 3x from both sides
-2y = -3x + 6
Divide both sides by -2
For the second problem, simply manipulate the equation.
Distribute
Subtract 2x from both sides
Add 6 to both sides
For the third problem, do the same thing.
We must first multiply both sides by 4.
Distribute
Subtract 4x from both sides
Add 3 to both sides
Divide both sides by 2
For number one, there will be an infinite number of solutions, as there are two placeholders.
3x - 2y = 6
It seems we can use the intercept method.
3x - 2(0) = 6
3x = 6
Divide both sides by 3
x = 2
This is one solution: (2,0)
3(0) - 2y = 6
-2y = 6
Divide both sidees by -2
y = -3
This is another solution: (0,-3)
You should now be able to draw the line.
If you want intercept form for this equation, just manipulate the equation in order to get the y = mx + b form.
Subtract 3x from both sides
-2y = -3x + 6
Divide both sides by -2
For the second problem, simply manipulate the equation.
Distribute
Subtract 2x from both sides
Add 6 to both sides
For the third problem, do the same thing.
We must first multiply both sides by 4.
Distribute
Subtract 4x from both sides
Add 3 to both sides
Divide both sides by 2