Question

50 POINTS HELP DUE IN 30 MINS!!!

Answer 1

9.

$4 < 5 < 9$

$2^2 < 5 < 3^2$

$2 < \sqrt 5 < 3$

$-3 < -\sqrt 5 < -2 < -1.96312...$

$-\sqrt 5 < -1.96312...$

10.

The least will be one of the negative ones, -3 or -6/5.  Since -6/5=-1.2, we see

-3 is the least

11.

81 < 90 < 100

$9^2 < 90 < 10^2$

$9 < \sqrt{90} < 10$

Answer: 10 feet

12.

We know $\sqrt 8 > \sqrt 5$ and $2.5 > 2 \frac 1 3$

Since

$2.5^2 = 6.25 < 8$

$\sqrt 8$  is the tallest.