Answer:
a=-2
So yep. ;)
Step-by-step explanation:
Alright, so, (2,12), 2 is the x and 12 is the y.
Stick them into the equation:
Then, solve:
a = -2
So yes, they're on the graph.
Hope this helped! :)
There are 9 computers and 72 students. What is the unit rate of students to computers? pleaase help meee
2 answers:
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Answer:
The median is 79
The median of the first quartile is 62
The median of the third quartile is 94.5
The inter quartile range is 32.5
Step-by-step explanation:
The median is the middle number of arranged number from smallest to greatest
The median of the first quartile is the middle number of the numbers before the median
The median of the third quartile is the middle number of the numbers after the median
The inter quartile range is the difference of the median of the 3rd quartile and the median of the 1st quartile
The numbers are 98, 64, 75, 57, 86, 60, 91, 98, 79
Let us arrange the numbers from small to big
57, 60, 64, 75, 79, 86, 91, 98, 98
They are 9 numbers
The middle one is the 5th number (4 before it and 4 after it)
The 5th number is 79
The median is 79
The numbers before the median are 57, 60, 64, 75
They are 4 numbers
The middle numbers are 2nd and 3rd
The median is the average of them
The 2nd number is 60 and the 3rd number is 64
The median of the first quartile = = 62
The median of the first quartile is 62
The numbers before the median are 86, 91, 98, 98
They are 4 numbers
The middle numbers are 2nd and 3rd
The median is the average of them
The 2nd number is 91 and the 3rd number is 98
The median of the third quartile = = 94.5
The median of the third quartile is 94.5
The inter quartile range = third median - first median
First median = 62
Third median = 94.5
Inter quartile range = 94.5 - 62 = 32.5
The inter quartile range is 32.5