Answer:
1. 0.0417
2. 0.1375
3. no
Step-by-step explanation:
lets define:
A as the probability that a car needs a warranty repair.
B as probability taht the car is manufactured by a company that is based in country X
we have the
prob(A) = 0.08
prob(B) = 0.60
prob(A∩B) = 0.025
a. we are to calculate the probability taht a car manufactured in country X needs a warranty repair.
= p(AIB) =
= 0.025/0.60
= 0.0417
2. Probability that car needs warranty repair given it was not manufactured in country X.
P(AIB')
= p(A∩B')/P(B')
= 0.08-0.025/1-0.60
= 0.055/0.40
= 0.1375
3. no, Need for warranty repair and location are not independent
your answer is 8 fluid ounces:)
Answer: $75
Step-by-step explanation: First he bought tires for 45.00 dollars - later sold it as 65.0 dollars.
=> 65 - 45 = 20 dollars is his profit
he brought 3 rims for 85 dollar - then later sold it as 126 dollars
=> 126 - 85 = 41 dollars
He bought headlight for 5.00 dollars then sold it later for 15 dollars.
=> 15 - 5 = 10 dollars
Total expenses
=> 134
Total amount sold
=> 209
Profit => 209 - 134 = 75 dollars
Answer:
(0,10.2)
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Using the cosine ratio in the right triangle and the exact value
cos45° = , then
cos45° = = = ( cross- multiply )
s × = 4 ( divide both sides by )
s = 4 → A