Question

NO LINKS!! Please help​

Answer 1

Answer:

FJ = 32

IJ = 24

FG = 48

Step-by-step explanation:

Getting Started with FG

$\frac{IH}{AB} =\frac{FG}{ED}$

$\frac{72}{36} =\frac{FG}{24}$

$\frac{FG}{24} =2$

$FG=24(2)=48$

The proportion between polygons is 2:1

$IJ=2CB$

$IJ=2(12)=24$

$FJ=2BC=2(16)=32$

Hope this helps

Answer 2

Answer:

FJ = 32

IJ = 24

FG = 48

Step-by-step explanation:

Given:  HGFJI ~ AEDCB

From inspection of the diagram, the corresponding sides are:

HG~AE

FG~DE

FJ~DC

IJ~CB

IH~BA

The only pair of sides that both have side lengths are IH and BA.  Therefore, we can use these to figure out the scale factor of dilation.

IH = 72   and   BA = 36

⇒ IH/BA= 72/36 = 2

Therefore, HGFJI is an enlargement of AEDCB by a scale factor of 2

If HG = 56

⇒ AE = 56 ÷ 2 = 28

If DE = 24

⇒ FG = 24 × 2 = 48

If DC = 16

⇒ FJ = 16 × 2 = 32

If CB = 12

⇒ IJ = 12 × 2 = 24