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Sedbober [7]
3 years ago
8

What is x/6-3=15 find for x

Mathematics
2 answers:
blsea [12.9K]3 years ago
5 0

Answer:

x=3

Step-by-step explanation:

x/6 -3 =15

Add the 3 to the other side.

x/6=18

Divide 18 by 6 to get the exponent by itself.

x=3

vichka [17]3 years ago
4 0

Answer:

x=108

Step-by-step explanation:

1. Solve for x

\frac{x}{6} -3=15

\frac{x}{6} =18

x=18*6

x=108

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Plz help simplify 8/10​
Free_Kalibri [48]

\frac{8}{10} → \frac{4}{5}

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Hope this helps :)

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Can someone help! I know the answer I just need step by step!
baherus [9]

Answer:

4 \sqrt{2}

Step-by-step explanation:

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\implies \sqrt{32}=\sqrt{16 \cdot 2

Apply exponent rule \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}

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2 years ago
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Graph ARST with vertices R(6, 6), S(3, -6), and T(0, 3) and its image after a
padilas [110]

Answer:

The answer is the second figure and the vertices of Δ R'S'T' are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

Step-by-step explanation:

* Lets revise some transformation

- If point (x , y) reflected across the x-axis

 ∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

 ∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

 ∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

 ∴ Its image is (-y , -x)

- Now we can solve the problem

∵ R = (6 , 6) , S = (3 , -6) , T = (0 , 3), they are the vertices of ΔRST

- The triangle RST is reflected over the y-axis

- According to the rule above the signs of x-coordinates will change

∵ R = (6 , 6)

∴ Its image is (-6 , 6)

∵ S = (3 , -6)

∴ Its image is (-3 , -6)

∵ T = (0 , 3)

∴ Its image is (0 , 3)

* Now lets look to the figure to find the correct answers

- The image of Δ RST is ΔR'S'T'

∵ The vertices of the image of ΔRST are:

  R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

* The answer is the second figure

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