The greatest common factor of the numbers is that which is the fused factors of all the numbers without the repetition of the common factors present in the given.
25·5·11 = 5·5·5·11
23·52·7 =23·2·2·13·7
Since, there are no repeated factors, the answer would be,
5·5·5·11·23·2·2·13·7
The answer unfortunately is not among the choices.
Answer:
Option B and C is correct
Step-by-step explanation:
<h3><u>Given</u>;</h3>
- Priya has 5 pencils, each x inches in length.
- Total length = 34.5 inches.
Now,
5 times x = 34.5
So,
5x = 34.5
34.5 ÷ 5 = x
Thus, 5x = 34.5 and 34.5 ÷ 5 = x are the answer
<u>-TheUnknownScientist 72</u>
Answer:
Step-by-step explanation:
Let the ends of the given segment are A and B.
Coordinates of A → (8, 6)
Coordinates of B → (12, 12)
If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,
(x, y) → (kx, ky)
If k = 
(x, y) → 
By this rule coordinates of the image points of A and B will be,
A(8, 6) → 
→ A'(5.3, 4)
B(12, 12) → 
→ B'(8, 8)
Now we can get the image of segment AB after dilation by a scale factor of
.
256.5/18= 14.25
(14.25x2)+(18x2)= 64.5m