Here’s an example on how to write one.
A. expanded, you get XxXxXxXxXxXxXxX over XxXxXxXxX
b.XxXxX or X³
c. I would just cancel out the 5 Xs on the top line against the 5 Xs on the bottom, leaving X³.
Answer:
there are 6 different ways they will not be next to each other
I think the answer is 1/16 because there is only one way that HTHT can fall out of 16 possible outcomes. That's what I think. Hope this helps!
Answer:
Step-by-step explanation:
dy/dx= -(2x+3y+1)/(3x-2y+1)
Let x= X+p. and y = Y+q. then dy/dx = dy/dX.
dy/dX= -(2X+2p+3Y+3q+1)/(3X+3p-2Y-2q+1) =
dy/dX = -{2X+3Y+(2p+3q+1)}/{3X-2Y+(3p-2q+1)}
Now 2p+3q+1=0……………..(1)
3p-2q +1=0…………………………(2)
p/(3+2)=q/(3–2)=1/(-4–9)
