First, to set up consecutive odd or even integers you have to add 2 to the previous integer.
Let x be the first integer,
(x + 2), (x + 4), and (x + 6)
Now set up the parameters they give:
3(x + x + 2) = x + 6 - 25
Solving:
Combine like terms and distribute on the left, combine like terms on the right.
3(2x + 2) = x - 19
6x + 6 = x - 19
Subtract x from both sides and subtract 6 from both sides.
5x = -25
Divide both sides by 5
x = -5
x + 2 = -5 + 2 = -3
x + 4 = -5 + 4 = -1
x + 6 = -5 + 6 = 1
Check:
3(-5 + -3) ?=? 1 - 25
-24 ?=? -24 CORRECT
Answer:
SUE: (18-x)-5
TONY: (18+x) / 
Sue has 18 sweets
Tony also has 18 sweets
Sue gives x sweets to Tony
Sue then eats 5 of her sweets
Tony then eats half of his sweets
(18-x)-5=(18+x)/ 1/2
x= -7.6
well 6 out of 42 is 1/7
double 42 and get 84.
Now to keep it even, you have to multiply 6x2
x/3-3 =x/9+3
add 3 to each side
x/3 = x/9 +6
subtract x/9 from each side
x/3 -x/9 = 6
get a common denominator
3/3*x/3 -x/9 = 6
3x/9 -x/9 =6
2x/9 =6
multiply each side by 9/2
x = 54/2
x=27
