Assignment: ![\bold{Simplify \ Equation: \ 3y^2-y+7y-y^2}](https://tex.z-dn.net/?f=%5Cbold%7BSimplify%20%5C%20Equation%3A%20%5C%203y%5E2-y%2B7y-y%5E2%7D)
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Answer: ![\boxed{\bold{2y^2+6y}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbold%7B2y%5E2%2B6y%7D%7D)
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Explanation: ![\downarrow\downarrow\downarrow](https://tex.z-dn.net/?f=%5Cdownarrow%5Cdownarrow%5Cdownarrow)
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[ Step One ] Group Like Terms In Equation Together
![\bold{3y^2-y^2-y+7y}](https://tex.z-dn.net/?f=%5Cbold%7B3y%5E2-y%5E2-y%2B7y%7D)
[ Step Two ] Combine Similar Elements
![\bold{-y+7y=6y}](https://tex.z-dn.net/?f=%5Cbold%7B-y%2B7y%3D6y%7D)
[ Step Three ] Rewrite Equation
![\bold{3y^2-y^2+6y}](https://tex.z-dn.net/?f=%5Cbold%7B3y%5E2-y%5E2%2B6y%7D)
[ Step Four ] Combine Similar Elements
![\bold{3y^2-y^2=2y^2}](https://tex.z-dn.net/?f=%5Cbold%7B3y%5E2-y%5E2%3D2y%5E2%7D)
[ Step Five ] Rewrite Equation
![\bold{2y^2+6y}](https://tex.z-dn.net/?f=%5Cbold%7B2y%5E2%2B6y%7D)
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Answer:
Find the distance between (-1, 1) and (3, 4).
This problem is solved simply by plugging our x- and y-values into the distance formula:
D=(3−(−1))2+(4−1)2−−−−−−−−−−−−−−−−−−√=
=16+9−−−−−√=25−−√=5
Sometimes you need to find the point that is exactly between two other points. This middle point is called the "midpoint". By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.
If the end points of a line segment is (x1, y1) and (x2, y2) then the midpoint of the line segment has the coordinates:
(x1+x22,y1+y22)
C because 3 + 7 is 10 and if it's greater the answer is 10 - 2 which is 8 so it reads 10 is greater than 8
Answer: 1.4
Step-by-step explanation: First, swap the sides of the equation so that the one with the variable can be in front.
So, its 2y=2.8
To solve this, you simply divide both sides of the equation by 2.
2 divided by 2 is 0. That leaves you with the y by itself. Then, 2.8 divided by 2 is 1.4
So, y=1.4
Answer:
37.50°
Step-by-step explanation:
The sum of both sides of an angle is 180°.
180° - 142.5° = 37.50°