Given:

Since the quadratic equation is equal to 0, we need to solve for x. Let's factor. Since a ≠ 1, we can easily solve. We need to find out what factors of 10 add up to 7. I know that 5*2 = 10 and 5+2 = 7. This fits out problem perfectly. Now that we have that, we can simplify it into two binomials:

Now, if it was not equal to zero, we would be done. However, we are not done. We need to set both terms equal to 0 to solve for x.

To isolate x, subtract 2 from both sides to cancel the +2 on the left.

Let's do the other one:

Same thing, subtract 5 from both sides to isolate x.

So, in conclusion, your solutions are:
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