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Dovator [93]
3 years ago
8

Jessie wants to buy jeans that retail at $42.00. the jeans are marked 10% off and jessie has a coupon for an additional 10% off.

what is the total cost for the jeans?
a. $37.80
c. $29.40
b. $34.02
d. $33.60 user: which of the following is not a typical type of sale you might find at a department store?
a. clearance sale
c. holiday sale
b. consignment sale
d. preseason sale
Mathematics
1 answer:
IRINA_888 [86]3 years ago
6 0
To your 1st question it 33.60 and your second question would be preseason sale
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3 years ago
(r3 +6r2 −21r−18)÷(r−3) solve using synthetic division
alexandr402 [8]

Answer:

y = x^2 + 9x + 6    No remainder.

Step-by-step explanation:

The divisor will be 3 The sign on the divisor switches.

3 || 1    +     6    -    21    -   18 ||

                 3         27     + 18

================================

      1          9         6          0


The answser is x^2 + 9x + 6

5 0
3 years ago
Help me plz !!!!!! i need help be honest
klemol [59]
THE ANSER is commutative property of addition
4 0
3 years ago
Let m = 6x +5.<br> Which equation is equivalent to (6x + 5)^2 – 10 = -18x – 15 in terms of m?
aev [14]

Answer: m² + 3m - 10 = 0

Step-by-step explanation:

From the expression, considering

6x + 5 = m

The original expression

( 6x + 5 )² - 10 = -18 - 15

Factorize the right hand expression,

-18 - 15 = -3( 6x - 15 )

Since m = 6x + 5 , we now substitute for m in that expression

m² - 10 = -3m

Now re arrange the equation in the form,

ax² - bx + c = 0

Now back to the equation,

m² + 3m - 10 = 0,

So the equivalent equation will be

m² + 3m - 10 = 0

7 0
3 years ago
A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju
weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

V_0 = 12 m/s

\theta = 20^0

g=9.8 m/s^2

At maximum height:

V_y = 0

Components of initial velocity:

V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s

V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s

To find time to reach maximum height:

V_y = V_0y -gt

Plugging in the known values:

0 = 4.10 - 9.8t

t = \frac{-4.10}{-9.8}

t = 0.418 s

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m

8 0
3 years ago
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