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alisha [4.7K]
4 years ago
13

Please help me answer this math question!

Mathematics
1 answer:
Sveta_85 [38]4 years ago
5 0
The answer is B. If you would like an explanation just comment.
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If y=3/x then y'=?<br><br>A)-y/x<br>B)y/x<br>C)-x/y<br>D)-3x/y<br>E)-y/3x
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y=\dfrac{3}{x}\\\\\\&#10;y'=\left(\dfrac{3}{x}\right)'=(3\cdot x^{-1})'=3\cdot(x^{-1})'=3\cdot(-1)\cdot x^{-2}=-3\cdot x^{-2}=\\\\\\=-\dfrac{3}{x^2}=-\dfrac{3}{x\cdot x}=-\dfrac{3}{x}\cdot\dfrac{1}{x}=-y\cdot\dfrac{1}{x}=-\dfrac{y}{x}

Answer (A)
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4 years ago
Simplify each equation. Tell whether the equation has one, no, or infinite solutions.
ANEK [815]

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3 years ago
An article suggests the uniform distribution on the interval (7.5, 19) as a model for depth (cm) of the bioturbation layer in se
mamaluj [8]

Answer:

a) Mean: 13.25

Variance: 11.02

b)

0 if x below than 7.5

{x-a}{b-a} is x in between 7.5 and 19

1 if x higher than 19.

Step-by-step explanation:

This is a problem in which we use the uniform probability distribution.

(a) What are the mean and variance of depth?

The mean is the midpoint of 7.5 and 19. So

M = \frac{7.5 + 19}{2} = 13.25

The mean is 13.25

The variance is given by the following formula:

V = \frac{(b-a)^{2}}{12}

In which b and a are the limits of the interval. So b = 19, a = 7.5

So

V = \frac{(b-a)^{2}}{12} = \frac{(19-7.5)^{2}}{12} = 11.02

The variance is 11.02.

(b) What is the cdf of depth?

The uniform probability distribution has a cummulative distribution function, of 0 if is below a, \frac{x-a}{b-a} for x in between a and b and 1 is x is greater than b.

So:

0 if x below than 7.5

{x-a}{b-a} is x in between 7.5 and 19

1 if x higher than 19.

6 0
4 years ago
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