Please help me answer this math question!
1 answer:
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We can write the sequence out more fully, as we can see each time it is divided by 6.
60, 60/6, 60/6^2, 60/6^3, and so on.
Therefore we know the sequence can be written as
You can think of this as a graph, i.e. y=60/6^(x-1)
As a result, as x tends to infinity, y tends to 0 (since it effectively becomes 60/infinity). Therefore the sequence converges toward zero.
60, 60/6, 60/6^2, 60/6^3, and so on.
Therefore we know the sequence can be written as
You can think of this as a graph, i.e. y=60/6^(x-1)
As a result, as x tends to infinity, y tends to 0 (since it effectively becomes 60/infinity). Therefore the sequence converges toward zero.
Answer:
b =
Step-by-step explanation:
To clear the radicals square both sides
=
( cross- multiply )
(6 - a)(8 + b) = b - 7 ← expand factors on left using FOIL
48 + 6b - 8a - ab = b - 7 ( subtract 48 from both sides )
6b - 8a - ab = b - 55 ( add 8a to both sides )
6b - ab = b - 55 + 8a ( subtract b from both sides )
6b - ab - b = 8a - 55, that is
5b - ab = 8a - 55 ← factor out b from each term on the left side )
b(5 - a) = 8a - 55 ← divide both sides by (5 - a)
b =
I hope this step by step explanation helps.
