All categories

3 years ago

Four students spent $12 on school lunch , At this rate , Find The Amount 10 students would spend on the same school lunch ?

1 answer:

6 0

Set up a proportion
4/12=10/x
cross multiply
120=4x
divide by 4
30=x
10 students would spend $30 on the same school lunch

You might be interested in

Guys what is the perfect square

umka2103 [35]

1,4,9,16,25,36,...,n^2
since they all have rational square roots
3asy

8 0

3 years ago

Read 2 more answers

Uma empresa de taxi cobra a bandeira de 5,00 ainda o valor de 1,50 para cada quilometro rodado determine a lei da funçâo corresp

weqwewe [10]

Answer:

y = 5 + 1.5x

Step-by-step explanation:

The law of function would be shown below:

Let us assume that the amount charged by the taxis of this company is equivalent to y.

And, x is the amount of kilometers traveled.

So as per the given statement, the taxi charged $5 plus $1.50 per km

Therefore the law of function would be

y = 5 + 1.5x.

7 0

3 years ago

In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d

nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

Download pdf

3 0

4 years ago

What are the first 5 terms of an arithmetic sequence with a common difference of – 0.4 and the first term of 0.7?

vovikov84 [41]

A no is the correct ans .

5 0

3 years ago

Read 2 more answers

Hey I need help fast it's due tomorrow

adelina 88 [10]

Is that even possible

5 0

3 years ago