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elena-14-01-66 [18.8K]
2 years ago
10

Find the inequality represented by the graph

Mathematics
2 answers:
bezimeni [28]2 years ago
4 0
The answer is y ≥ 1/2x
GaryK [48]2 years ago
4 0

Answer:

y\geq \frac{1}{2}x

Step-by-step explanation:

To find the inequality represent by the graph, we first must find the linear equation that represents that line.

So, in first place, we find the slope of the line, using two point (0,0) and (2,1):

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }=\frac{1-0}{2-0}=\frac{1}{2}

Now, using one point, the slope and the slope-point formula, we find the linear expression

y-y_{1}=m(x-x_{1})\\y-0=\frac{1}{2}(x-0)\\ y=\frac{1}{2}x

Then, with the linear expression, we just need to take a test point form the shaded area and evaluate the expression, the point is gonna be (0,1):

y=\frac{1}{2}x\\1=\frac{1}{2}(0)\\ 1=0

We know that 1 is more than zero, this means that the right inequality sign is \geq, due to the relation of the numbers, and because line is solid.

Therefore, the inequality is

y\geq \frac{1}{2}x

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nata0808 [166]

Answer:

Step-by-step explanation:

let's try a:

-4*4x-4*(-17) - expand the distributing terms

-16x-4*(-17) - simplify

-16x-(-68) - simplify again

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-16x+68 does not equal to 16x-68

lets try b:

-28x+3... dont know what u mean

lets try c:

13-34 first

-21

lets try d:

0-17

-17

lets try e:

-2x+(8-8)

-2x

fortunally dont know what you mean.

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2 years ago
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Answer: fx-7f+3\\

graph

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2 years ago
The airport has a moving walkway that moves at 2 feet per second. Suppose Calvin can travel 152
Rudiy27

Answer:

0.94 ft/sec

Step-by-step explanation:

Airport: 2 feet per second.

Total distance 152 ft in the same amount of time it takes him to talk 72 feet on the pavement.

152/2 = 76 - This is how many seconds he was walking in the airport.

He walked 76 seconds and moved 152 feet.

So that means if the SAME time was used so 76 seconds he walked 72 feet, then we can do 72ft/76sec to get 0.94ft/sec

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