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Dafna1 [17]
3 years ago
7

If (x+3) varies directly as y and x=3 when y=12, what is the value of x when y=8?

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

Answer:

x = 1.

Step-by-step explanation:

y = k(x + 3)

When x = 3 y = 12 so

12 = k(3 + 3)

6k = 12

k = 2.

So the relation is y = 2(x + 3)

When y is 8:

8 = 2(x + 3)

2x = 8 - 2*3 = 2

x = 1.

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Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass funct
Basile [38]

This question is incomplete, the complete question is;

Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

determine;

a) P( X < 2.5 )

B) P( 0.75 < X ≤ 1.5 )

Answer:

a) P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 ) = 0.5

Step-by-step explanation:

Given the data in the question;

The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

a) P( X < 2.5 )

P( X < 2.5 ) = p[ x = 0 ] + p[ x = 0.5 ] + p[ x = 1 ] + p[ x = 1.5 ] + p[ x = 2 ]

so

P( X < 2.5 ) = 0.1 + 0.2 + 0.3 + 0.2 + 0.1

P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 )

P( 0.75 < X ≤ 1.5 ) = p[ x = 1 ] + p[ x = 1.5 ]

so

P( 0.75 < X ≤ 1.5 ) = 0.3 + 0.2

P( 0.75 < X ≤ 1.5 ) = 0.5

3 0
3 years ago
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