If (x+3) varies directly as y and x=3 when y=12, what is the value of x when y=8?
1 answer:
Answer:
x = 1.
Step-by-step explanation:
y = k(x + 3)
When x = 3 y = 12 so
12 = k(3 + 3)
6k = 12
k = 2.
So the relation is y = 2(x + 3)
When y is 8:
8 = 2(x + 3)
2x = 8 - 2*3 = 2
x = 1.
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