3 years ago

If (x+3) varies directly as y and x=3 when y=12, what is the value of x when y=8?

Mathematics

1 answer:

slavikrds [6]3 years ago

6 0

Answer:

x = 1.

Step-by-step explanation:

y = k(x + 3)

When x = 3 y = 12 so

12 = k(3 + 3)

6k = 12

k = 2.

So the relation is y = 2(x + 3)

When y is 8:

8 = 2(x + 3)

2x = 8 - 2*3 = 2

x = 1.

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