Answer:
<em>Interval notation: [0, 2.236]</em>
<em>Set Builder notation: </em>
Step-by-step explanation:
Given that:
Equation of height of the ball dropped from a height of 10 foot, as:
Where 
is the time since the ball was dropped.
To find:
The domain of the function in Interval and set builder notation.
Solution:
<em>Domain of a function </em>is defined as the set of valid input values that can be given to the function for which the function is defined.
Here, input is time.
We can not have negative values for time.
Therefore, starting value for time will be <em>0 seconds</em>.
And the value of height can not be lesser than that of 0 ft.
Maximum value for time can be 2.236 seconds.
Therefore the domain is:
<em>Interval notation: [0, 2.236]</em>
<em>Set Builder notation: </em>
Answer:
AC ≈ 5.03
Step-by-step explanation:
We can solve the problem above using the trigonometric ratio, they are;
SOH CAH TOA
sin Ф = opposite / hypotenuse
cosФ= adjacent/ hypotenuse
tan Ф = opposite / adjacent
From the diagram above, in reference to angle B;
opposite =AC and adjacent =BC
Since we have opposite and adjacent, the best formula to use is
tanФ = opposite / adjacent
tan B = AC / BC
tan 40 = AC/ 6
Multiply both-side of the equation by 6
6× tan 40 = AC/ 6 × 6
At the right-hand side of the equation, 6 will cancel-out 6 leaving us with just AC
6×tan 40 = AC
5.034598 = AC
AC ≈ 5.03 to the nearest hundredths
Answer:
x = 4
Step-by-step explanation:
Step 1: Subtract 4 from both sides.
5x+4−4=24−4
5x=20
Step 2: Divide both sides by 5.
5x
5
=
20
5
x=4
you welcome love
The issue I observe is that Ms.Beebe needs to slow tf down
Answer:
( 5x + 1 ) ( x - 4 )
Step-by-step explanation:
5x² - 19x - 4
= 5x² + x - 20x - 4
= x ( 5x + 1 ) - 4 ( 5x + 1 )
= ( 5x + 1 ) ( x - 4 )
Hence, factorized.
