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3 years ago

The store bought a pair of shoes for $40 and sold it for $90. What percentage was the mark up?

Mathematics

1 answer:

Charra [1.4K]3 years ago

3 0

Answer: I think the markup is 66.67%

Step-by-step explanation:

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The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If

frutty [35]

For this case we have the following equation:
$w = 0.9* \sqrt{E}$
Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:
$w = 0.9* \sqrt{12}$
Making the corresponding calculation:
$w=3.12$
Answer:
the approximate weight of the spring in pounds is:
$w=3.12$

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3 years ago

Read 2 more answers

Please answer thank you !!!!!

KonstantinChe [14]

Answer:

-7x^3+8x^2+x-5

Step-by-step explanation:

We are simply adding the two functions:

f(x) + g(x) = (2x^2-5x^3+x-7) + (6x^2-2x^3+2) = 8x^2-7x^3+x-5 = -7x^3+8x^2+x-5

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2 years ago

A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the

amm1812

Answer:

$s(t)=(ln|7|+ln|2|)\,ft$

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

$a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\$

Integrating both sides w.r.to t

$v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\$

Using initial value

$v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}$

We have to calculate the distance covered in time interval [0,5], so:

$\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft$

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3 years ago

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choli [55]

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What is a hundred box?

ANEK [815]

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