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lord [1]
2 years ago
5

10 small and 8 large cost $192. 20 small and 1 large cost $99. What is cost of a small

Mathematics
2 answers:
seraphim [82]2 years ago
7 0

Answer:

Step-by-step explanation:

small=s,    s=3.99

large=l,       l=19.20

10s+8l=192.20

20s+l=99

we can see that in the second equation, 20s+l=99

l=99-20s

lets replace l in the first equation

10s+8(99-20s)=192.20

10s+792-160s=192.20

-150s=-792+192.20

150s=599.80

s=3.99

l=99-20(3.99)=99-79.80=19.20

Sphinxa [80]2 years ago
6 0

Answer:

19

Step-by-step explanation:

You can set up a system of equations.

x=small, and y = large.

10x+8y=$192

20x+1y=$99

you can multiply the first equation by -2 to get rid of x:

20x+1y=$99

-20x-16y=-$384

when you combine them, you get:

-15y=$-285

you can divide by -15 and you get:

y=19, so 1 large equals $19

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In Ryan coorporation the first shift produced 5 1/2 times as many lightbulbs as the second shift. if the total lightul.bs produc
dimaraw [331]

Answer:

  • first shift: 13,750 bulbs
  • second shift: 2500 bulbs

Step-by-step explanation:

The production ratio is ...

  shift 1 : shift 2 = 5.5 : 1 = 11 : 2

so, the production on shift 1 as a ratio to the total is ...

  shift 1 : total = 11 : (11+2) = 11 : 13

The first shift produced ...

  (11/13)(16,250 bulbs) = 13,750 bulbs . . . . first shift

and the second shift produced ...

  (2/13)(16,250 bulbs) = 2,500 bulbs . . . . second shift

_____

Of course, once you have one of the numbers, you can also find the other by using the 5.5 factor or by subtracting from total production.

3 0
4 years ago
Permutations of the word "Congratulations"​
Mice21 [21]

Answer:

There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is  14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is  14!/(23)=10,897,286,400

5 0
3 years ago
Ted has $3.90. He has only dimes and quarters. He has 27 coins altogether. How many of each does he have
mestny [16]

Answer: 8 quarters 19 dimes

Step-by-step explanation:

we already know 8+19=27, if 4 quarters equals a dollar then you use 4 quarters each to create 2 dollars.

then, use 10 dimes to create another dollar summing it up to $3. now all we have to do is make 90 cents, and we've already used 18 coins.

if we used another 9 dimes, that would equal 90 cents.

in conclusion, 4+4= 8

8+10= 18

18+9= 27, and having $3.90

6 0
3 years ago
Need help asap for test
alex41 [277]

Answer:

a=4 and b=-1

Step-by-step explanation:

2(4)+3(-1)= 5

6 0
3 years ago
Figure ABCD is reflected across the x-axis. What are the coordinates of A' , B' , C' , and D' ? Enter your answer in each box.
stealth61 [152]

Answer:

The coordinates of ABCD after  the reflection across the x-axis would become:

  • A'(2, -3)
  • B'(5, -5)
  • C'(7, -3)
  • D'(5, -2)

Step-by-step explanation:

The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:

  • x-coordinate of the point does not change, but
  • y-coordinate of the point changes its sign

In other words:

The point P(x, y) after reflection across x-axis would be P'(x, -y)

P(x, y)        →       P'(x, -y)

Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:

P(x, y)        →       P'(x, -y)

A(2, 3)       →       A'(2, -3)      

B(5, 5)       →       B'(5, -5)

C(7, 3)        →      C'(7, -3)

D(5, 2)       →       D'(5, -2)

Therefore, the coordinates of ABCD after  the reflection across the x-axis would become:

  • A'(2, -3)
  • B'(5, -5)
  • C'(7, -3)
  • D'(5, -2)

8 0
3 years ago
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