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2 years ago

If the area of the face of a cube is 16 square meters, find the cubeâs volume.

Mathematics

1 answer:

Bogdan [553]2 years ago

3 0

4x4x4=64. Hope that helps

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P(x)=x4-52+9x+8 Hallar p(-3)

ozzi

Answer:

P(x)=x⁴+9x-44

Step-by-step explanation:

6 0

3 years ago

Evaluate the summation below. ) (-1 + 6d) d=2

weqwewe [10]

Answer:

− 1 + 6 d , d = 2

Step-by-step explanation:

4 0

2 years ago

Seth has one less than twice the number of compact discs (CDs) that Jason has. Raoul has 53 more CDs than Jason. If Seth gives J

ELEN [110]

S = 2J - 1
R = J + 53
S - 25 = J + 25...S = J + 50

2J - 1 = J + 50
2J - J = 50 + 1
J = 51 <===Jason has 51 CD's

R = J + 53
R = 51 + 53
R = 104 <===Raoul has 104 CD's

S = 2J - 51
S = 2(51) - 1
S = 102 - 1
S = 101 <===Seth has 101 CD's

4 0

3 years ago

Evaluate the expression (2x + y) - z when x= 3, y = 4, z =5

Lapatulllka [165]

Answer:

Step-by-step explanation:

(2x + y) - z

Let x=3 y=4 and z=5

2*3 +4 -5

Multiply and divide first

6 +4 -5

Then add and subtract

10-5

5 0

2 years ago

Please help with the question in the picture!

Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

METHOD - I

Sin² C + Cos² C = 1

Cos² C = 1 - Sin² C

Cos² C = $1 - \frac{9}{25}$

Cos² C = $\frac{25 - 9}{25}$

Cos² C = $\frac{16}{25}$

Cos C = $\sqrt{\frac{16}{25} }$

Cos C = $\frac{4}{5}$

As we know that

Tan C = $\frac{Sin C}{Cos C }$

Tan C = $\frac{\frac{3}{5} }{\frac{4}{5} }$

Tan C = $\frac{3}{4}$ 

METHOD - II

Given Sin C = $\frac{3}{5} = \frac{Height}{Hypotenuse}$

therefore,

AB ( Height ) = 3; BC ( Hypotenuse) = 5

∵ ΔABC is Right triangle.

∴ By Pythagorean Theorem-

AB² + AC² = BC²

AC² = BC² - AB²

AC² = 5² - 3²

AC² = 25 - 9

AC² = 16

AC ( Base) = 4

Since,

Tan C = $\frac{Height}{Base}$ 

Tan C = $\frac{AB}{AC}$

Hence Tan C = $\frac{3}{4}$ 

4 0

2 years ago