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3 years ago

(5-12)^2+8/(-2) help pleaaaaase

Mathematics

1 answer:

OlgaM077 [116]3 years ago

8 0

(5-12)^2+8/(-2)
(-7)^2+8/(-2)
(49)+8/(-2)
(49)+(-4)
45

Using PEMDAS, your answer would be 45.

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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

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2 years ago

Triangle XY Z is similar to triangle ABC.

garri49 [273]

Answer:

13.5

Step-by-step explanation:

12/4=3

9/3=3

4.5x3=13.5

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-Dominant- [34]

X=1, because they both have the same height (y), so they'll cross each other!

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3 years ago

What is the unit rate for meters per second if a car travels 238 meters in 17 seconds?

madreJ [45]

I assume a unit rate is simply ms^-1 or whatever.

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If in 17 seconds it travels 238 metres, that means in 1 second it travels 238/17m=14m

Therefore the unit rate (speed) of the car is 14m/s or 14ms^-1

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Step-by-step explanation:

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