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miskamm [114]
4 years ago
4

Triangle WXY has the interior and exterior angles shown below.

Mathematics
2 answers:
gayaneshka [121]4 years ago
7 0
180 - 122 = 58

x + 2x - 13 + 58 = 180
3x + 45 = 180
3x = 135
  x = 45

m<W = 2(45) - 13 = 90 - 13 = 77

answer
D. 77
Alex4 years ago
7 0

Answer:  Fourth option is correct.

Step-by-step explanation:

Since we have given that

∠ W = (2x-13)°

∠Y = x°

exterior ∠X = 122°

We know that "Sum of interior angles is equal to exterior angles":

\angle W+\angle Y=122^\circ\\\\2x-13+x=122^\circ\\\\3x-13=122^\circ\\\\3x=122+13\\\\3x=135^\circ\\\\x=\dfrac{135}{3}\\\\x=45^\circ

So, the measure of angle W is given by

2x-13\\\\=2\times 45-13\\\\=90-13\\\\=77^\circ

Hence, Fourth option is correct.

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Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

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Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

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The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

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The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

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The mass of Tea B in the mixture = 10 lb - x

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The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

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x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

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