Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
K = 5 or k = 3
Hope it helps-,-
3+4 = 7
so
21 / 7 3
3 x 3 = 9
3 x 4 = 12
answer
£21 in ratio 3:4 is £9:£12
Answer:
1.00
Step-by-step explanation:
$34.50 divided by 3 equal 11.50 and $42 divided 4 equal 10.50 subtract that and get 1.00 so leah earned a dollar more per hour
Answer:
P (She selects the route of four specific capitals) = 
D. No,it is not practical to list all of the different possible routes because the number of possible permutations is very large.
Step-by-step explanation:
Let's start assuming that each route is equally likely to be chosen.
Assuming this, we can calculate P(A) where the event A is ''She selects the route of four specific capitals'' doing the following :
P(A) = Favourable cases in which the route of four specific capitals is selected / Total number of ways in 4 of 42 states
The favourable cases in which the route of four specific capitals is selected is equal to 1 .
For the denominator we need the permutation number of 4 in 42.
The permutation number is defined as :


The probability of event A is : 
Finally for the other question : The option D is the correct because the number of possible permutations is 2686320 and is very large to be listed.