All categories

3 years ago

The smallest hummingbird is the Bee hummingbird. It has a mass of about 1

Mathematics

1 answer:

Mrac [35]3 years ago

3 0

This question is incomplete and has not be written correctly.

Complete Question:

The smallest hummingbird is the Bee hummingbird. It has a mass of about 1 1/2 grams. The mass of a larger type of hummingbird is about 5 times the mass of the Bee hummingbird.

What is the mass of the larger humming bird?

Answer:

7 1/2 grams

Step-by-step explanation:

The mass of Bee humming bird is given in the question as = 1 1/2 grams

Mass of the larger humming bird = 5 times the mass of Bee humming bird

The mass of the larger humming bird is calculated as:

5 × 1 1/2 grams = 5 × 3/2 grams

= 15/2 grams = 7 1/2 grams

Therefore, the mass of the larger humming bird is 7 1/2 grams

You might be interested in

5th grade math. Correct answer will be marked brainliest.

dezoksy [38]

The Answer is : 2,2

5 0

3 years ago

During a game of pool, Mia hit a ball and it followed the path from B to C and then to D. The angles formed by the path are cong

dybincka [34]

C.43 in because you got to think about it then you haft to add

8 0

3 years ago

Read 2 more answers

If a is a negative number and b is a negative which expression is correct?

zlopas [31]

Answer:

U have to say the numbers for me to figure out the problem

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The tallest man alive today is 8 feet 3 inches. How tall is he in inches?

juin [17]

Answer:

99 inches

It should be correct, you can try and double check with goo gle though.

6 0

3 years ago

Read 2 more answers

Can someone please explain how to solve this? And give me the answer?! THANK U !

Lyrx [107]

we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.

$\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76$

4 0

3 years ago