Answer:
<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>
Step-by-step explanation:
Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units
From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.
By the definition of rhombus, diagonals meet at right angles.
Implies that PQ = QA
x+2 = 3x - 14
x-3x=-14-2
-2x=-16
2x = 16
dividing by 2 on both sides, we will get,

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>
The line segment 


( since x=8)


<h3>∴

units</h3>
The slope is 8.
(5,40) (10,80)
80-40=40
10-5=5
40/5=8
Answer:
raise ^that 4 to the power of -1+2 like this
raise ^to the power -2 like this
5-2=3 <Awnser
Hello!
4 (x-12) ^ 1/3 = -16
Step 1. Simplify each side of the equation, 4/
3x + −16 = −16 and 4
/3
x −16 = −16
Step 2. Add 16 to both sides, 4
/3
x − 16 + 16 = −16 + 16
Step 3: Multiply both sides by 3/4, (
3/4)*(4/3x)=(3/4)*(0)
Final Answer: x= 0
Hope I could help! :)
Answer:
There is no picture.
Step-by-step explanation: