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3 years ago

There are more inches on a football field (100 yards) than there are centimeters on a 28 meter basketball court true or false

Mathematics

2 answers:

PIT_PIT [208]3 years ago

6 0

Answer:

The given statement is True

Step-by-step explanation:

WE have to find out that which one has more no of inches

so now we have

100 yards football field

28 meter basketball court

Total no of inches in one yard = 36 inches

Total no of inches in 100 yard = 36 * 100

= 3600 inches

Now total no of inches in one meter = 39.3701 inches

Total no of inches in 28 meter = 28 * 39.3701

=1102.3628 inches

So we can see that 1102.3628 is smaller than 3600

So It can also be seen that football field has more inches then a basketball court

So the given statement is True

scoundrel [369]3 years ago

4 0

Answer:

The given statement is true.

Step-by-step explanation:

First we will apply conversions to given terms:

1 yard has = 36 inches

So, 100 yards has = $36\times100=3600$ inches.

1 meter = 100 cm

So, 28 meters has = $28\times100=2800$ cm

So, now upon comparing we can see that 3600 is greater than 2800.

Therefore, the inches in a 100 yard field are greater than the cm in a 28 meter basketball court.

The statement given here is true.

You might be interested in

Determine which of the lines are parallel and which of the lines are perpendicular. Select all of the statements that are true.

slega [8]

Answers:

Line A is parallel to line D.

Line A is perpendicular to line C.

Line C is perpendicular to line D.

=====================================================

Explanation:

Let's use the slope formula to calculate the slope of the line through (-1,-17) and (3,11)

$(x_1,y_1) = (-1,-17) \text{ and } (x_2,y_2) = (3,11)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{11 - (-17)}{3 - (-1)}\\\\m = \frac{11 + 17}{3 + 1}\\\\m = \frac{28}{4}\\\\m = 7\\\\$

The slope of line A is 7

-------------

Now let's find the slope of line B.

$(x_1,y_1) = (0,4) \text{ and } (x_2,y_2) = (7,-5)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-5 - 4}{7 - 0}\\\\m = -\frac{9}{7}\\\\$

-------------

Now onto line C.

$(x_1,y_1) = (7,1) \text{ and } (x_2,y_2) = (0,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 1}{0 - 7}\\\\m = \frac{1}{-7}\\\\m = -\frac{1}{7}\\\\$

-------------

Lastly we have line D.

$(x_1,y_1) = (-1,-6) \text{ and } (x_2,y_2) = (1,8)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{8 - (-6)}{1 - (-1)}\\\\m = \frac{8 + 6}{1 + 1}\\\\m = \frac{14}{2}\\\\m = 7\\\\$

------------------------------

Here's a summary of the slopes we found

$\begin{array}{|c|c|} \cline{1-2}\text{Line} & \text{Slope}\\\cline{1-2}\text{A} & 7\\\cline{1-2}\text{B} & -9/7\\\cline{1-2}\text{C} & -1/7\\\cline{1-2}\text{D} & 7\\\cline{1-2}\end{array}$

Recall that parallel lines have equal slopes, but different y intercepts. This fact makes Line A parallel to line D.

Lines A and C are perpendicular to one another, because the slopes 7 and -1/7 multiply to -1. In other words, -1/7 is the negative reciprocal of 7, and vice versa. These two lines form a 90 degree angle.

Lines C and D are perpendicular for the same reasoning as the previous paragraph.

Line B unfortunately is neither parallel nor perpendicular to any of the other lines mentioned.

You can use a graphing tool like Desmos or GeoGebra to verify these answers.

6 0

1 year ago

Evaluate 0.3 + y/2 when y = 10 and z =5

Vladimir79 [104]

Answer:

0.3*10+10/5

PEMDAS (left to right)

3+2

Step-by-step explanation: