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3 years ago

There are more inches on a football field (100 yards) than there are centimeters on a 28 meter basketball court true or false

Mathematics

2 answers:

PIT_PIT [208]3 years ago

6 0

Answer:

The given statement is True

Step-by-step explanation:

WE have to find out that which one has more no of inches

so now we have

100 yards football field

28 meter basketball court

Total no of inches in one yard = 36 inches

Total no of inches in 100 yard = 36 * 100

= 3600 inches

Now total no of inches in one meter = 39.3701 inches

Total no of inches in 28 meter = 28 * 39.3701

=1102.3628 inches

So we can see that 1102.3628 is smaller than 3600

So It can also be seen that football field has more inches then a basketball court

So the given statement is True

scoundrel [369]3 years ago

4 0

Answer:

The given statement is true.

Step-by-step explanation:

First we will apply conversions to given terms:

1 yard has = 36 inches

So, 100 yards has = $36\times100=3600$ inches.

1 meter = 100 cm

So, 28 meters has = $28\times100=2800$ cm

So, now upon comparing we can see that 3600 is greater than 2800.

Therefore, the inches in a 100 yard field are greater than the cm in a 28 meter basketball court.

The statement given here is true.

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Examine the data below for a stalk of corn. Logarithmic regression Use logarithmic regression to find an equation of the form y

masya89 [10]

The value of a and b for the data values of stalk of corn using the logarithmic regression is -76.2038 and 37.6735 respectively.

<h3>What is logarithmic regression?</h3>

Logarithmic regression is a type of regression which is used to model the statement in which the growth or decay initially at rapid rate, and then slow down with respect to time.

The data of the table for the day and height of the stalk of corn is listed below.

Day (x) 9 12 22 40

Height (y) in 5 17 45 60

Mean of x values,

$m_x=\dfrac{9+12+22+40}{4}\\m_x=17.5581$

Mean of y values,

$m_y=\dfrac{5+17+45+60}{4}\\m_y=31.75$

For the above table, the value of correlation coefficient is 0.99133. For these values, the logarithmic regression can be given as,

$y = -76.2038+37.6735\ln(x)$

Compare it with the following logarithmic regression equation, we get

$y = a+b\ln(x)$

$a=-76.2038\\b=37.6735$

Hence, the value of a and b for the data values of stalk of corn using the logarithmic regression is -76.2038 and 37.6735 respectively.

Learn more about the logarithmic regression here;

brainly.com/question/25226042

5 0

2 years ago

angle EFG and angle GFH are a linear pair, m angle GFH= 2n+38 and m angle GFH=2n+38. what are m angle EFG and m angle GFH

motikmotik

Answer:

Part 1) m∠EFG=94°

Part 2) m∠GFH=86°

Step-by-step explanation:

we know that

m∠EFG+m∠GFH=180° -----> by linear pair (given problem)

we have

m∠EFG=3n+22

m∠GFH=2n+38

substitute the values

(3n+22)°+(2n+38)°=180°

Solve for n

(5n+60)=180

5n=180-60

5n=120

n=24

Find the measure of angle EFG

m∠EFG=3n+22

substitute the value of n

m∠EFG=3(24)+22=94°

Find the measure of angle GFH

m∠GFH=2n+38

substitute the value of n

m∠GFH=2(24)+38=86°

5 0

3 years ago

Read 2 more answers

I really need help with this equation as soon as possible :D

viktelen [127]

The subtraction sign in front of the second set of parenthesis changes the signs on the terms inside those parenthesis. So this could be rewritten as $x-3x^4+2x^2+x^3-4x^6$ . None of the exponents on the x are the same, so we will just express it in terms of descending powers of x. $-4x^6-3x^4+x^3+2x^2+x$ . This is also the same as $4x^6+3x^4-x^3-2x^2-x$ if you don't like to start with a negative. Either one is correct.

7 0

3 years ago

Show another way to write 100 more than 623

____ [38]

There are many ways, but here is one:

x = 100

Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623

Answer: x + 623 (Make sure you define your ‘x’ value)

4 0

3 years ago

In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,

aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0

3 years ago