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Anarel [89]
3 years ago
10

The graph shows how much a plant grew after it was purchased. Which statement is not correct?

Mathematics
1 answer:
Luda [366]3 years ago
3 0

Answer:

The plant grows 1 cm every day is the incorrect statement

Step-by-step explanation:

The graph shows that for every 10 days the plant grows 1 cm

10/2 = 5

so in 5 days the plant would grow half of what it does in 10 days so 1/2 or 0.5 cm

10/10 = 1

so in 1 day the plant would grow a tenth of what it does in 10 days so 1/10 or 0.1 cm

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(3x – 70) (3y+40) 120 x
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3x-70

Step-by-step explanation:

(3y+40 ) 120x is the answer of that question answer

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If nicholas spends $8.10 on pixie sticks,then how many pounds did he purchase?
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how much does 1 pound cost?

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Find the distance between the points given.<br><br> (-3, 2) and (9, -3)<br><br> √(61)<br><br> √(37)
cricket20 [7]

Answer:

d=13.

Step-by-step explanation:

d=\sqrt{(x_{2}-x_{1} ) ^{2} +(y_{2}-y_{1} ) ^{2}}

From question statement, x_{1} =-3   ,x_{2} =9

y_{1} =2  ,y_{2} =-3

put above values in the distance formula,we obtain

d=\sqrt{(9-(-3))^{2}+(-3-2)^{2}}

d=\sqrt{(12)^{2}+(-5)^{2}}

d=\sqrt{144+25}

d=\sqrt{169}

d=13


8 0
3 years ago
Find the slope of the line whose equation is 3x+6y=9. <br> How do I solve this?
nirvana33 [79]
If you need to get to nine the answer is...
6+3 or 3x1+6
8 0
3 years ago
The nth term of a sequence is 3n^2- 1
Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √(  (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √(  (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √(  (31 - 2^2)/3)  = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

5 0
3 years ago
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