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3 years ago

What is the distance between (0,-1), (5,1)

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

7 0

Answer:

square root of 29 or approximately 5.38

Mazyrski [523]3 years ago

6 0

Here you go! I hope this helps.

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50 POINTS <br><br>Help me plzz i need help with this it is due tomorrow

jeyben [28]

Answer:

5 cups

Step-by-step explanation:

hi! to find the sum of the soup mix, we have to add all the fractions together.

7/4 + 1/2 + 5/3 + 1/3 +1/4 + 1/2

we have to find a common denominator for each, which is the LCM of the denominators. this would be 12. let's change the fractions so we can add them up.

21/12 + 6/12 + 20/12 + 4/12 + 3/12 + 6/12

add the numerators and keep the denominators the same.

(21+6+20+4+3+6)/12

60/12

this simplifies to 5.

the total amount of soup mix is 5 cups.

3 0

3 years ago

Read 2 more answers

Find the area of the shape shown.

Step2247 [10]

Answer:

well area is the space inside of a shape. so you would multiply 2 by 4 because there are 4 sides.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Jon said, “m-1 is always greater than 1-m. Do you agree with Jon? LIURE DOMPE DI EL דים כר LECCE RE: A. Agree, because m is a po

Trava [24]

Given that Jon said,

"m-1 is always greater than 1-m"

we want to find how true the statement is;

$\begin{gathered} \text{for m = positive integer.} \\ m=5 \\ m-1=5-1=4 \\ 1-m=1-5=-4 \\ So,\text{ } \\ m-1>1-m \\ \text{for m equals positive integer } \end{gathered}$

secondly for negative values of m;

$\begin{gathered} m=-5 \\ m-1=-5-1=-6 \\ 1-m=1-(-5)=1+5=6 \\ So, \\ m-1$

So, the statement "m-1 is always greater than 1-m" is false.

Because 1- m is greater than m-1 when m is a negative integer.

Therefore, I Disagree, because 1- m is greater than m-1 when m is a negative integer

3 0

2 years ago

An object is launched vertically upward from a 25 foot platform and is modeled by the function s(t)=−16t2+11t+25.

ch4aika [34]

Correct option:

d. 1.64

<h2>Explanation:</h2>

An object is launched vertically upward from a 25 foot platform and is modeled by the following function:

$s(t)=-16t^2+11t+25$

So this is the equation of a parabola because the object is a projectile so it follows the Projectile Motion.

The object fall back to the ground when $s(t)=0$ so:

$-16t^2+11t+25=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ t_{12}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ a=-16 \\ \\ b=11 \\ \\ c=25 \\ \\ \\ t_{12}=\frac{-11\pm \sqrt{11^2-4(-16)(25)}}{2(-16)} \\ \\ t_{12}=\frac{-11\pm 41.48}{-32} \\ \\ t_{1}=\frac{-11+ 41.48}{-32}=-0.95s \\ \\ t_{2}=\frac{-11- 41.48}{-32}=1.64s$