Answer:
y=2x^2−16x+30
Step-by-step explanation:
PLSSSSSSS BRAINLIEST
<span>We want to optimize f(x,y,z)=x^2 y^2 z^2, subject to g(x,y,z) = x^2 + y^2 + z^2 = 289.
Then, ∇f = λ∇g ==> <2xy^2 z^2, 2x^2 yz^2, 2x^2 y^2 z> = λ<2x, 2y, 2z>.
Equating like entries:
xy^2 z^2 = λx
x^2 yz^2 = λy
x^2 y^2 z = λz.
Hence, x^2 y^2 z^2 = λx^2 = λy^2 = λz^2.
(i) If λ = 0, then at least one of x, y, z is 0, and thus f(x,y,z) = 0 <---Minimum
(Note that there are infinitely many such points.)
(f being a perfect square implies that this has to be the minimum.)
(ii) Otherwise, we have x^2 = y^2 = z^2.
Substituting this into g yields 3x^2 = 289 ==> x = ±17/√3.
This yields eight critical points (all signage possibilities)
(x, y, z) = (±17/√3, ±17/√3, ±17/√3), and
f(±17/√3, ±17/√3, ±17/√3) = (289/3)^3 <----Maximum
I hope this helps! </span><span>
</span>
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Answer:
(a) a squared + 15 squared = 17 squared
Step-by-step explanation:
The Pythagorean theorem tells you the sum of the squares of the sides is equal to the square of the hypotenuse.
a^2 + 15^2 = 17^2 . . . . . . matches the first choice
Answer:
6 square root of 2
Step-by-step explanation:
sin theta = opposite / hypotenuse
sin 45 = 6/x
Multiply by x
x sin 45 = 6
Divide by sin 45
x sin 45/ sin 45 = 6 / sin 45
x = 6/ sin 45
x = 6/ (1/sqrt(2))
x = 6 sqrt(2)