How can a regular hexagon be folded to show that it has reflections symmetry

2 answers:

6 0

It can be folded by the up covering the down, it can be folded by the left or the right covering one another, you can even do it diagonally. Any angle of the hexagon covering the one on the opposite side will show reflections symmetry.

evablogger [386]3 years ago

3 0

You have to fold it straight in half.

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PLEASE HELP!

emmainna [20.7K]

Use the given recursion and starting value of $x_0 = 2.4$ to find $x_1$ :

$x_1 = \dfrac{x_0 + \frac6{x_0}}2 = \dfrac{2.4 + \frac{6}{2.4}}2 = 2.45$

Do the same for $x_2$ and $x_3$ :

$x_2 = \dfrac{x_1 + \frac6{x_1}}2 = \dfrac{2.45 + \frac6{2.45}}2 \approx 2.44949$

$x_3 = \dfrac{x_2+\frac6{x_2}}2 \approx \dfrac{2.44949 + \frac6{2.44949}}2 \approx \boxed{2.44949}$

(That's not a mistake. This just tells you that the 2nd and 3rd iterates are very close together and have at least the same first 5 digits after the decimal.)

5 0

1 year ago

Which of the functions below could have created this graph?

bearhunter [10]

Answer:

Step-by-step explanation:

Two facts need to guide your answer.

One

The highest power is odd: you know this because an even power would start on the left come down do it's squiggles if had any and wind up on the right going up.

This graph comes down on the left does it's squiggles and then goes further down on the right. That's the behavior of something whose highest power is odd.

Two

The leading coefficient, the number in front of the highest power must be minus. If it was positive as in y = x^3 the graph would be the mirror image of what it is.

Argument

B and D cannot be true. The highest power is even.

C is false because the leading coefficient is + 1.

So that leave A which is the answer.

The graph is included with this answer