Answer:
- <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>
Explanation:
<u>Rewrite the table and the choices for better understanding:</u>
<em>Enrollment at a Technical School </em>
Year (x) First Year f(x) Second Year s(x)
2009 785 756
2010 740 785
2011 690 710
2012 732 732
2013 781 755
Which of the following statements is true based on the data in the table?
- The solution to f(x) = s(x) is x = 2012.
- The solution to f(x) = s(x) is x = 732.
- The solution to f(x) = s(x) is x = 2011.
- The solution to f(x) = s(x) is x = 710.
<h2>Solution</h2>
The question requires to find which of the options represents the solution to f(x) = s(x).
That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.
The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>
Thus, the correct choice is the third one:
- The solution to f(x) = s(x) is x = 2012.
You have to input each solution into the equation.
let’s start of with (12,0)
12-9(0)=12
12=12 <— which is true so it’s this one
let’s do the other ones to check
now let’s do (0,12)
0-9(12)=12
-108=12 <— not true
(3,-1)
3-9(-1)=12
13=12 <— not true
(0,-4/3)
0-9(-4/3)= 12
12=12 <— also true
the answer would be (12,0) and (0,-4/3). i’m not sure whether or not it’s a select all that apply question. i hope this helps
7 and 1/2+6 and 3/4+7 and 1/3=7+1/2+6+3/4+7+1/3=7+6+7+1/2+3/4+1/3=20+1/2+3/4+1/3
convert bottom nubmer to same (12)
1/2 times 6/6=6/12
3/4 times 3/3=9/12
1/3 times 4/4=4/12
20+6/12+9/12+4/12=20+19/12=20+1+7/12=21+7/12=21 and 7/12
answer is 21 and 7/12 hour or 21.58 hour or 21 hour and 35 minutes
No, because when adding 1 to any odd number it will become even, and all even numbers besides 2 are not prime. This means that if n was 1 the resulting number would be prime, since 2 is prime.
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