I want you to imagine as you read this or you can draw through the help of my explanation and see yourself:
1↪Draw triangle ABC where BC>AC
2↪D is any point on AC such that CD=CB
3↪Roughly drawing , you can assume CD=CB and and join BD
4↪SO triangle ABC which is a big triangle is divided into Triangles ABD and BDC
5↪See in triangle BDC ,CD=CB so, base angles of isosceles triangle are equal:
<CDB=<CBD = x (assume) which means x is acute angle since CDB and CBD are are in same triangle with same measure and there can't be any two obtuse angle in any traingle. So x must be acute.
6↪Now see in traingle ABD,
<ADB=180-<CDB=180-x=obtuse angle
...check yourself ...just subtract any acute angle from 180 you will get only obtuse angle (ie angle greater than 90)
That means in triangle ABD , one angle ADB is obtuse which means remaining <ABD and < BAD are acute. [PROVED]
❇Main Concept Used Here:
↪In any triangle there can be maximum of one obtuse angle...so remaining two must be acute angle otherwise interior angles sum can't be equal to 180.
Answer:
4) J
5) D
Step-by-step explanation:
4) 416 = 2x² - 6x
2x² - 6x - 416 = 0
x² - 3x - 208 = 0
x² - 16x + 13x - 208 = 0
x(x - 16) + 13(x - 16) = 0
(x - 16)(x + 13) = 0
x = 16, -13(not possible)
So 16 rows
5) y = a(x - h)² + k
y = a(x - 3)² - 7
When x = 1, y = -10
-10 = a (1 - 3)² - 7
-10 = 4a - 7
4a = -3
a = -¾
y = -¾(x - 3)² - 7
1. You have that the Standard form for the equation of a circle when its center is at the origin, is:
x²+y²=r²
2. You must calculate the radius. Then:
r=√(x²+y²)
x=24
y=32
3. When you substitute the values of "x" and "y" into the equation r=√(x²+y²), you obtain:
r=√(x²+y²)
r=√(24²+32²)
r=√(576+1024)
r=√1600
r=40 feet
4. Therefore, the diameter (D) of the circle, is:
D=2r
D=2(40 feet)
D=80 feet
4 kg because p (momentum) = m • v and p / v = m.
So 12 kg m/s divided by 3 m/s = 4 kg
The answer has something to do with volume.
