Need answer asap evaluate the limit or state that the limit does not exist 7n-8n/2n

Mathematics

1 answer:

bagirrra123 [75]4 years ago

4 0

$\lim_{n \to \ 0 } \frac{7n-8n}{2n} = \lim_{n \to \ 0 } \frac{-n}{2n} 
= \lim_{n \to \ 0 } \frac{-1}{2} = \frac{-1}{2}$

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What is 2/5 ÷ 4 2/3

Vikentia [17]

Answer:

3/35

Step-by-step explanation:

2/5 ÷ 14/3

2/5 × 3/14

= 3/35

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3 years ago

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the perimeter of a rectangle is 50 inches the length l is twice the width w. what is the area of the rectangle?? ❗️show work❗️

mr Goodwill [35]

Hey. Let me help you on this one.

In order for us to solve this problem, we will need to set up an equation which we can solve later. I will also be attaching an image with the work shown in case you don't understand my explanation. Make sure to read over it since it will help you with your studies.

We know that the length is twice the width, meaning that $a=2b$ , with "a" standing for length, and "b" standing for width. Now that we have formed an equation for length, we can actually form an equation for perimeter.

$P=2(2b)+2b$

Let's simplify the equation so it's easier and less confusing for us to solve it.

$50=6b$

Let's divide 6 from both sides, thus eliminating all variables except for b on the right side.

$8.3=b$

"3" in 8.3 is repeating. This is very important to remember. Now, we know the width of the triangle. Let's find the length of the triangle so we can then multiply both numbers together and find the area.

$a=8.3*2$
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"6" in 16.6 is repeating as well. It's crucial to remember as well. We know the values now, meaning that we can find the area of the rectangle.

$S=16.6*8.3$
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Answer: Area of the rectangle is 138.8 (with 8 repeating).

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4 years ago

Mrs. Braddock has a bag containing 6 lipsticks, 4 eye shadows, 6 eye liners, and 5 mascaras. She will randomly choose one item f

Slav-nsk [51]

Answer:

The probability that she will not pull lipstick is 71%.

Step-by-step explanation:

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable number of outcomes

N = total number of outcomes

The contents in Mrs. Braddock's bag are:

Number of lipsticks = n (L) = 6

Number of eye shadows = n (S) = 4

Number of eye liners = n (E) = 6

Number of mascaras = n (M) = 5

Total number of items in the bag = N = 21

Consider that the probability of an event occurring is P. Then the probability of the given event not taking place is known as the complement of that event.

Complement of the given event is, 1 – P.

Compute the probability of selecting a lipstick as follows:

$P(L)=\frac{n(L)}{N}\\\\=\frac{6}{21}\\\\=\frac{2}{7}$