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MrMuchimi
3 years ago
11

A __?__ to a theorem is a statement that follows immediately from the theorem.

Mathematics
2 answers:
AysviL [449]3 years ago
6 0

Answer:

<h2>Corollary.</h2>

Step-by-step explanation:

The complete statement would be

A corollary to a theorem is a statement that follows immediately from the theorem.

A corollary is defined as a true proposition derived from a theorem, which is a true statement that was demonstrated.

In geometry there are plenty corollaries which can be seeing as deduction, which are true because they are deducted by theorems which are true.

For example, there is a theorem that states <em>"two angles that form a straight angle are supplementary"</em>. And a corollary of that theorem is <em>"where two lines intersect, opposite angles are equal"</em>

DaniilM [7]3 years ago
3 0
A conclusion to a theorem is a statement that follows immediately from the theorem. <span> In a conditional </span>statement<span>, the </span>statement<span> that </span>immediately follows<span> the word then is the conclusion. Hope this answers the question. Have a nice day.</span>
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Step-by-step explanation:

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3 0
4 years ago
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Find the cube roots of 27(cos 330° + i sin 330°)
Aleksandr-060686 [28]

Answer:

See below for all the cube roots

Step-by-step explanation:

<u>DeMoivre's Theorem</u>

Let z=r(cos\theta+isin\theta) be a complex number in polar form, where n is an integer and n\geq1. If z^n=r^n(cos\theta+isin\theta)^n, then z^n=r^n(cos(n\theta)+isin(n\theta)).

<u>Nth Root of a Complex Number</u>

If n is any positive integer, the nth roots of z=rcis\theta are given by \sqrt[n]{rcis\theta}=(rcis\theta)^{\frac{1}{n}} where the nth roots are found with the formulas:

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  • \sqrt[n]{r}\biggr[cis(\frac{\theta+2\pi k}{n})\biggr] for radians

for  k=0,1,2,...\:,n-1

<u>Calculation</u>

<u />z=27(cos330^\circ+isin330^\circ)\\\\\sqrt[3]{z} =\sqrt[3]{27(cos330^\circ+isin330^\circ)}\\\\z^{\frac{1}{3}} =(27(cos330^\circ+isin330^\circ))^{\frac{1}{3}}\\\\z^{\frac{1}{3}} =27^{\frac{1}{3}}(cos(\frac{1}{3}\cdot330^\circ)+isin(\frac{1}{3}\cdot330^\circ))\\\\z^{\frac{1}{3}} =3(cos110^\circ+isin110^\circ)

<u>First cube root where k=2</u>

<u />\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(2)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+720^\circ}{3})\biggr]\\3\biggr[cis(\frac{1050^\circ}{3})\biggr]\\3\biggr[cis(350^\circ)\biggr]\\3\biggr[cos(350^\circ)+isin(350^\circ)\biggr]

<u>Second cube root where k=1</u>

\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(1)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+360^\circ}{3})\biggr]\\3\biggr[cis(\frac{690^\circ}{3})\biggr]\\3\biggr[cis(230^\circ)\biggr]\\3\biggr[cos(230^\circ)+isin(230^\circ)\biggr]

<u>Third cube root where k=0</u>

<u />\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(0)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ}{3})\biggr]\\3\biggr[cis(110^\circ)\biggr]\\3\biggr[cos(110^\circ)+isin(110^\circ)\biggr]

4 0
3 years ago
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aivan3 [116]
T= MN+R
I believe that this is the right answer
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3 years ago
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klasskru [66]
9 (c - 6) = 63
9c - 54 = 63
9c = 117
c = 13
6 0
3 years ago
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