Question

PLEASE AWNSER THIS SOON AS YOU CAN

Answer 1

Using the concept of probability, it is found that:

a) 0.26 = 26% probability that a randomly selected person from this group likes country music.

b) 0.28 = 28% probability that a randomly selected person from this group likes rock music and is from the North.

c) 0.27 = 27% probability that a randomly selected person from this from this group likes oldies given that they are from the South.

d) P(R) = 0.44.

e) P(S) = 0.53.

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• A probability is given by the number of desired outcomes divided by the number of total outcomes.
• In this problem, these number of outcomes are drawn from the two-way table.

Item a:

• Out of 312 people, 81 like country music.

Thus:

$p = \frac{81}{312} = 0.26$

0.26 = 26% probability that a randomly selected person from this group likes country music.

Item b:

• Out of 312 people, 88 like rock and are from the north.

Thus:

$p = \frac{88}{312} = 0.28$

0.28 = 28% probability that a randomly selected person from this group likes rock music and is from the North.

Item c:

• 164 people from the South, of those 44 like oldies.

Thus:

$p = \frac{44}{164} = 0.27$

0.27 = 27% probability that a randomly selected person from this from this group likes oldies given that they are from the South.

Item d:

• 138 people out of 312 like rock, thus:

$P(R) = \frac{138}{312} = 0.44$

P(R) = 0.44.

Item e:

• 164 people out of 312 are from the South, thus:

$P(S) = \frac{164}{312} = 0.53$

P(S) = 0.53.

A similar problem is given at brainly.com/question/24161830