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damaskus [11]
3 years ago
13

A rectangular solar panel has a length that is 13 inches shorter than 4 times its width. if the perimeter of the panel is 174 ​i

nches, what are the dimensions of the​ panel?
Mathematics
1 answer:
natta225 [31]3 years ago
5 0
W= width
l= 4w-13

Perimeter= 2l+2w
Substitute (4w-13) for l

174=2(4w-13)+2w
174=8w-26+2w
174=10w-26
Add 26 to both sides
200=10w
Divide both sides by 10
20 inches= w

Substitute the answer to find length.
l=4w-13
l=4(20)-13
l=80-13
l=67 inches

Check:
174= 2(67)+2(20)
174=134+40
174=174

Hope this helps! :)
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Doug has joined a job with a starting salary of $30000 per year.  

Hence, if a₁ is the salary of Doug in the first year, then  

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Now, each year Doug will receive a raise of $3000 in his salary.

Hence, in the 2nd year, his salary(a₂) will become ( a₁ +3000) per year.

Again, in the 3rd year, his salary(a₃) will become ( a₂ +3000) per year.

Therefor, in the similar manner the recursive formula for his salary in each year will be given as a_{n} =a_{n-1} +3000 and a₁ =30000 for n = 2,3,4,5,6, ...... {aₙ is the yearly salary of Doug in the nth year} (Answer)

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*Quadratic equations*<br>solve<br>(i) (x+3)(x-4)=0<br><br>(ii) (2x-3)(x-1) =0​
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3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

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Answer:

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