Hey there! :)
Answer:
b = -11.
Step-by-step explanation:
Create an equation in slope-intercept form to solve for the intercept:
y = mx + b
Plug in the slope and point values:
4 = -3(-5) + b
Simplify:
4 = 15 + b
Solve for b:
-11 = b
b represents the y-intercept, therefore:
y-intercept = -11
Though these segments aren't marked congruent in the diagram, the two lines inside the circle making up the bases of the triangles are congruent as all radii are congruent. So the triangles are congruent by SAS.
4 because you would say "forty three thousand..." three would be the one thousands place, and 4 would be the ten thousands place.
In three dimensions, the cross product of two vectors is defined as shown below

Then, solving the determinant

In our case,

Where we used the formula for AxB to calculate ixj.
Finally,

Thus, (i+j)x(ixj)=i-j
If you are asking for an equation for this statement, it would be y = x + 5