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Rasek [7]
3 years ago
7

A regular tube of toothpaste costs $2.50 for 3.2 ounces. A travel size tube costs $1.00 for 1.2 ounces. Compare the prices and w

eights using percent to decide which is the better buy. ​
Mathematics
1 answer:
Elanso [62]3 years ago
3 0

Answer:

The regular size is more economical.

Step-by-step explanation:

Consider the provided information.

A regular tube of toothpaste costs $2.50 for 3.2 ounces.

Find out the unit rate as shown below:

\frac{\$2.50}{3.2}=\$0.78

Therefore, the cost of one ounce is $0.78.

A travel size tube costs $1.00 for 1.2 ounces.

Find out the unit rate as shown below:

\frac{\$1}{1.2}=\$0.833

Therefore, the cost of one ounce is $0.833.

From the above calculation we can observe that regular tube toothpaste price is better buy.

Now find the percent as shown:

Firs find the difference

$0.83-$0.78 = $0.05

Therefore,

\frac{0.05}{0.78}\times 100\approx 6.41

Hence, regular tube is 6.41% less costly as compare to travel size.

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Triangle KNM is shown. Triangle K N M is shown. Angle M K N is 25 degrees. Angle K N M is 130 degrees. Angle N M K is 25 degrees
mars1129 [50]

Answer:

<h3>Two of the sides of triangle KNM are the equal</h3>

Step-by-step explanation:

From the triangle KNM, we can see that two of the angles M K N and Angle N M K are the same. If two of the angles are equal this means that two of the sides of the triangles are also equal. This type of triangle is known as an ISOSCELES TRIANGLE.

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2 years ago
Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the
mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

f(x)=Le^{-Lx}

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

f(x)=e^{-x}

For a)

P(T>2)

P(T>2)=1-P(T\leq 2)

P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx

P(T>2)=1-(-e^{-2}+1)

P(T>2)=e^{-2}=0.1353

For b)

P(T\geq 10/T>9)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

P(T\geq 10/T>9)=P(T\geq 1)

P(T\geq 1)=1-P(T

P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679

4 0
3 years ago
10 of the x power= 100000000​
zheka24 [161]

Answer:

x=8

Step-by-step explanation:

5 0
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Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16
sweet-ann [11.9K]

Answer:

x=\frac{1}{4}

Step-by-step explanation:

<u>Given:</u>

2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)

<u>Use the Power Rule Law:</u>

log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)

<u>Use the Quotient Rule Law:</u>

log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})

<u>Use the Product Rule Law:</u>

log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})

<u>Simplify:</u>

log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})

\frac{4}{9}=\frac{8\sqrt{x}}{9}

4=8\sqrt{x}

\frac{4}{8}=\sqrt{x}

\frac{1}{2}=\sqrt{x}

\frac{1}{4}=x

5 0
2 years ago
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