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3 years ago

11

Sally makes 7 out of every 10 shots she takes during practice. If this pattern were to continue, how many would she make during

the game if she took 30 shots?

2 answers:

kvv77 [185]3 years ago

7 0

Answer:

21/30

Step-by-step explanation:

$\frac{7}{10} X 3$

$\frac{7}{10} X \frac{3}{3} = \frac{21}{30}$

Levart [38]3 years ago

4 0

Answer:

21

Step-by-step explanation:

7 for first 10 shots
7 for another 10 shots
7 for last 10 shots

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A botanist collected one leaf at random from each of 10 randomly selected mature maple trees of the same species. The mean and t

Zarrin [17]

Answer:

One sample t-test for population mean would be the most appropriate method.

Step-by-step explanation:

Following is the data which botanist collected and can use:

Sample mean
Sample Standard Deviation
Sample size (Which is 10)
Distribution is normal

We have to find the best approach to construct the confidence interval for one-sample population mean. Two tests are used for constructing the confidence interval for one-sample population mean. These are:

One-sample z test for population mean
One-sample t test for population mean

One sample z test is used when the distribution is normal and the population standard deviation is known to us. One sample t test is used when the distribution is normal, population standard deviation is unknown and sample standard deviation is known.

Considering the data botanist collected, One-sample t test would be the most appropriate method as we have all the required data for this test. Using any other test will result in flawed intervals and hence flawed conclusions.

Therefore, One-sample t-test for population mean would be the most appropriate method.

8 0

4 years ago

Resuelve estas ecuaciones<br> 1. x I 6 = 14<br> X=

valentinak56 [21]

Answer:

3 sjshgegegegehsksksjsjsissjs

5 0

3 years ago

The table below shows the fifth powers of different numbers:

Lera25 [3.4K]

Part A. Yes, because y=f(x)=x⁵.
Part B. f(4)=2(4)+12=8+12=20.

5 0

3 years ago

Determine the measure of angle A, B, and C in triangle ABC. If m∠A=(x-10)°,m∠B=(2x-50)°,and m∠C=x°

Effectus [21]

Answer:

m∠A = 50°

m∠B = 70°

m∠C = 60°

Step-by-step explanation:

Determine the measure of angle A, B, and C in triangle ABC. If m∠A=(x-10)°,m∠B=(2x-50)°,and m∠C=x°

In a Triangle, the sum of the interior angles of a triangle = 180°

Step 1

We solve for x

Hence:

m∠A + m∠B + m∠C= 180°

(x-10)°+ (2x-50)°+ x° = 180°

x - 10 + 2x - 50 + x = 180°

4x - 60 = 180°

4x = 180° + 60°

4x = 240°

x = 240°/4

x = 60°

Step 2

Solving for each measure

x = 60°

m∠A=(x-10)°

= 60° - 10°

= 50°

m∠B=(2x-50)°

= 2(60)° - 50°

= 120° - 50°

= 70°

m∠C=x°

= 60°

7 0

3 years ago

Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha

irinina [24]

Answer:

$n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401$

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Solution to the problem

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

The margin of error desired for this case is $ME= \pm 0.02$ equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is $\hat p =0.5$

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.96$

Now we have all the values needed and if we replace into equation (b) we got:

$n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401$

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0

4 years ago