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BARSIC [14]
3 years ago
12

Four less than the difference of a number x, squared and 6; X=2

Mathematics
1 answer:
algol [13]3 years ago
5 0
USE QUIZLET IT TELLS

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1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle
zimovet [89]

Answer: \left |  2t-5\right |,\ 2,\ 2t-5

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

s(t)=t^2-5t+1

Speed of the particle is given by

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left |  2t-5\right |

Acceleration of the particle is

\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2

velocity can be negative, but speed cannot

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5

3 0
3 years ago
Find the difference of 58.2–27.674.<br> a. 30.652<br> b. 30.526<br> c. 35.026<br> d. 35.620
d1i1m1o1n [39]

Answer:

B. 30.526

Step-by-step explanation:

Just subtract.

58.20

-27.674

30.526

7 0
3 years ago
Read 2 more answers
As an estimation we are told £3 is €4.
agasfer [191]

Answer:

21

Step-by-step explanation:

7 0
3 years ago
NOT SURE PLEASE HELP​
777dan777 [17]
2 units i believe but not entirely sure
4 0
3 years ago
Read 2 more answers
Need help ASAP PLEASE!!!!
stepan [7]
Look at the face of the pyramid facing you.  The length of the base of this pyramid is 82 m; half of that is 41 m.  

If you were to draw a straight vertical line through the vertex of the pyramid, the bottom of this line would be at the very center of the base and also be 41 in perpendicular distance from any of the edges of the base of this pyramid.

Let the height of the pyramid be y, as measured upward from the center of the base of the pyramid.  This center is, as before, 41 m from any side of the pyramid base, a horiz. distance.

Then, tan 52 deg = y / 41 m, and so y = height of pyramid =

(41 m)(tan 52 deg)  = (41 m) (1.28) = 52.48 m
6 0
4 years ago
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