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Citrus2011 [14]

3 years ago

5

Kim borrowed $400 from her parents to purchase a new cell phone. The table represents Kim's repayment schedule. Which inequality

states the domain of the relation?

2 answers:

Mekhanik [1.2K]3 years ago

5 0

The domain tells you about the independent variable, number of payments made. So the inequality should be smallest number of payments made ≤ variable representing payments ≤ largest number of payments made. The smallest number of payments is 0 and the largest is 8, so you'll have <span><span>
0≤variable≤8</span></span>

Gennadij [26K]3 years ago

4 0

The answer is {0 ≤ x ≤ 8} I took a test with this question and got it right.

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It takes one super giant pizza to feed three people if you invite 36 people how many peaches will you need

denis23 [38]

$\bf \begin{array}{ccll}
\stackrel{super~duper}{pizza}&folks\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&3\\
p&36
\end{array}\implies \cfrac{1}{p}=\cfrac{3}{36}\implies \cfrac{1\cdot 36}{3}=p$

8 0

3 years ago

What is the rate of 70 miles in 2 hours in unit rate

tamaranim1 [39]

You want one of the values in the ratio to be one for a unit rate. First, write out the ratio. It is 70 miles/2 hours. It's better not to include decimal numbers when you write a ratio when you can, so we're going to make the hours the unit rate. To make 2 -> 1 hour, divide both sides of the ratio by 2. 70/2 = 35.
The unit rate is 35 mi./hr.
Hope that helped you.

5 0

3 years ago

Read 2 more answers

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Which is the better buy? 5-pack of toaster pastries for $4.13 or 9-pack of toaster pastries for $7.56

kolbaska11 [484]

Answer: <em>The answer is </em><u><em>9-pack of toaster pastries for $7.56</em></u>

Step-by-step explanation:

<em>Basicly it would be more expensive if you bought 9 for the first option but less for the other.</em>

5 0

3 years ago

767074 rounded to the nearest hundred thousand

andriy [413]

767,074 rounded to the nearest hundred thousand is 800,000.

8 0

3 years ago

Read 2 more answers