Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
Answer: 8:9
Step-by-step explanation: Two find this answer, you need to see what will be the greatest number they can divide by (greatest common divider), it needs to be the same number for both 18 and 16. What number can go into both numbers, and is the greatest number? The answer is two, now you divide 2 by 18 and 16, so you'll get 8:9.
Hope this helps have a BLESSED and wonderful day! :-)
-Cutiepatutie
1 would be D.
2. Is A since 3^2=9 and -3^2=9 And 9-9=0. Im pretty sure A. For number 3. Just because the two x-values are 3 and -3. I’m sorry if I’m wrong on #3.
Answer:
10,500
Step-by-step explanation:
You must divide 52,500 by 5.
5 goes into the 5 in 52,500 one time. 5-5 is 0. 5 doesn't go into 2 so put a 0. 5 goes into 25 five times. 25-25 is 0. 5 goes into 5 one time. subtract and add the zeros at end. And you get 10,500
Answer:
hey it's you again. daniel
