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yuradex [85]
3 years ago
15

Mark wants a new car that costs $30000. He only has $500 in his savings account and $300 in his checking account. Which financin

g option should he chose
Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer: He should choose the savings account because he can earn more interest and the money in his savings account is more than the money in his checking account.

Step-by-step explanation:

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Evaluate the expression 2(8 - 4)^2 - 10 / 2
Artemon [7]
2(8-4)^2-5
16-32-5
-21





you can change the -10/2 to a -5 and it will be easier.
5 0
3 years ago
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I NEED THIS ASAP 5/8 of 48 is equal to 8/15 of some number. What is this number?
murzikaleks [220]

(5/8) × 48 = (8/15) × n

Multiply by the inverse of the coefficient of n. That inverse is 15/8.

n = (15/8)×(5/8)×48 = (75/64)×48 = 225/4 = 56 1/4

5/8 of 48 is equal to 8/15 of 56 1/4

5 0
3 years ago
The glee club has $90 to spend on pens and pencils. Each pen costs $0.75 and each pencil costs $0.15. Let x represent the number
Deffense [45]

Answer:

part a: answer b. 0.75x + 0.15y = 90

8 0
3 years ago
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Laura's school is holding an outdoor activities celebration event for its 20th anniversary. Laura decides to participate in the
Pachacha [2.7K]

Probabilities are used to determine the chances of Laura winning an activity

  • The value of p is 1/12
  • The expected score of the game is -1/6
  • The probability that she has a total score of 5 after two rounds is 0

<h3>How to calculate the value of p</h3>

To calculate the value of p, we make use of the following probability formula

\sum P(x) = 1

So, we have:

\frac 3{12} + \frac 1{12} + \frac 4{12} + \frac 2{12} + p + \frac 1{12} = 1

Collect like terms

\frac 3{12} + \frac 1{12} + \frac 4{12} + \frac 2{12} + \frac 1{12}  + p= 1

Evaluate the sums, on the left-hand side

\frac{11}{12} + p = 1

Subtract 11/12 from both sides

p = \frac 1{12}

Hence, the value of p is 1/12

<h3>(b) How to calculate the expected score</h3>

This is calculated using the following expected value formula

E(x) = \sum x * P(x)

So, we have:

E(x) = -3 * \frac{3}{12} -1 * \frac 1{12} + 0 * \frac 4{12} + 1 * \frac 2{12} + 2 * \frac 1{12} + 4 * \frac 1{12}

Evaluate the products

E(x) =  -\frac{9}{12} - \frac 1{12}  + \frac 2{12} + \frac 2{12} + \frac 4{12}

E(x) =  -\frac 2{12}

Simplify

E(x) =  -\frac 1{6}

Hence, the expected score of the game is -1/6

<h3>(c) The probability that she has a total score of 5 after two rounds</h3>

From the table, we have:

P(5) = 0

For after two rounds, we make use of the following equation

P(5) * P(5) = 0 * 0

P(5) * P(5) = 0

Hence, the probability that she has a total score of 5 after two rounds is 0

Read more about probabilities at:

brainly.com/question/25870256

4 0
2 years ago
Tan(x+pi) + 2sin(x+pi)=0<br><br>can you help prove this and make the left side equal the right?
vladimir1956 [14]

This is not an identity but an equation. You're supposed to find the values of x for which this is true. It is *not* true for all values of x.

To see why:

\tan x has period \pi, which means \tan(x+\pi)=\tan x.

The angle sum identity for \sin x says that

\sin(x+\pi)=\sin x\cos \pi+\cos x\sin\pi=-\sin x

So

\tan(x+\pi)+2\sin(x+\pi)=\tan x-2\sin x

By definition of \tan x,

\tan x=\dfrac{\sin x}{\cos x}

and so

\tan x-2\sin x=\sin x\left(\dfrac1{\cos x}-2\right)

which is only 0 if either \sin x=0 (which only happens for certain values of x) or \dfrac1{\cos x}-2=0\implies\cos x=\dfrac12 (which also only happens for certain values of x). It's these values of x you want to find.

\sin x=0 whenever x is a multiple of \pi, i.e. x=n\pi for any integer n.

If 0\le x, then \cos x=\dfrac12 is true for x=\dfrac\pi3 and x=\dfrac{5\pi}3. Then to account for all other possible values, we add a multiple of 2\pi, so that x=\dfrac\pi3+2n\pi or x=\dfrac{5\pi}3+2n\pi for integers n.

5 0
3 years ago
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