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igomit [66]
2 years ago
9

Write (−3) (−3)(−3) (−3) using exponents.

Mathematics
2 answers:
Tanya [424]2 years ago
8 0
-3^4 (Three to the Fourth power)
Butoxors [25]2 years ago
4 0

Answer:

-3^4

Step-by-step explanation:

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1) What is the area of square of length 5cm?
ASHA 777 [7]

Answer:

20 is my answer and the question is somehow confusing

7 0
2 years ago
Resuelve el siguiente ejercicio:
exis [7]

Answer:

Cuanto dinero voy a pagar  24 $

Cuanto recibiré de cambio  76 $

Step-by-step explanation:

Mis compras son:

1 lápiz       3,50 $

2 plumas  7,90 $

1Libreta   12,60 $

Lo que quiere decir que compre:

3,50 + 7,90 + 12,60  =  24 $

Si cancelo mis compras con un billete de 100 $ me tienen que dar vuelto por:

100 $  -  24  $  =  76 $

5 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Consider the eq
Deffense [45]

To solve for x in terms of b, simply treat b as a number, and solve for x as usual: first of all, we expand the left hand side:

-2bx+10 = 16

Subtract 10 from both sides:

-2bx = 6

Divide both sides by -2b:

x = \cfrac{6}{-2b} = \cfrac{-3}{b}

This means that in particular, if we set b= 3, we have

x = \cfrac{-3}{3} = -1

5 0
3 years ago
I don't know how to work this problem out
madam [21]
1/5(x-y) = 1
x+y = 9

x-y = 5 (x5)
x+y = 9

First you want to create both equations so at least one of the variables (x or y) are the same in both equations, so that is why I multiplied the top one by 5, you multiply the whole equation (both sides)

2x = 14
x = 7

Then you either Plus or minus one from the other, I plused the top one onto the bottom one, then solved for x

7 + y = 9
y = 2

Then put x back into one of the first two equations to get Y


4 0
3 years ago
Solve the following system of equations.<br> 2x+y=3<br> I= 2y - 1<br> x=<br> y=
marin [14]

<em>Note: I am assuming your second equation is:</em>

<em>x = 2y - 1</em>

<em></em>

Answer:

The solution to the system of equations is:

  • x = 1
  • y = 1

Step-by-step explanation:

Given the system of equations

2x+y=3

x = 2y - 1

solving the system of equations using the elimination method

\begin{bmatrix}2x+y=3\\ x=2y-1\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2x+y=3\\ x-2y=-1\end{bmatrix}

Multiply x-2y=-1 by2:     2x-4y=-2

\begin{bmatrix}2x+y=3\\ 2x-4y=-2\end{bmatrix}

subtracting the equations

2x-4y=-2

-

\underline{2x+y=3}

-5y=-5

now solve -5y = -5 for y

-5y=-5

Divide both sides by -5

\frac{-5y}{-5}=\frac{-5}{-5}

Simplify

y=1

For 2x+y=3 plug in y=1

2x+1=3

subtract 1 from both sides

2x+1-1=3-1

Simplify

2x=2

Divide both sides by 2

\frac{2x}{2}=\frac{2}{2}

Simplify

x=1

Therefore, the solution to the system of equations is:

  • x = 1
  • y = 1
8 0
3 years ago
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