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Sindrei [870]
3 years ago
8

1. Keith bought 6 baseball cards. His dog ate half of his collection and he was left with 36 cards. How many did he start with?

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0
1. Answer=66cards

Lets use the variable 'x' to represent the number of baseball cards in Keith's collection that he started with. The following equation can be made.

(x+6)/2=36
multiply both sides by 2
x+6=72
subtract 6 from both sides
x=66 cards

2. Answer=$12

Lets use the variable 'a' to represent Sara's allowance. The following equation can be made:

(a/2)+7=13
subtract 7 from both sides
a/2=6
multiply both sides by 2
a=$12
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A rhombus and a square have one and the same side of 6 cm. The area of the rhombus is 4/5 of the area of the square. Find the he
Scilla [17]
The area of the square= bxh
= 6x6= 36
The area of the rhombus is 4/5 the area of the square so 36x 4/5 = 28.8
Area of rhombus = basexheight
28.8= 6x height
Height = 28.8/6
Height =4.8
7 0
3 years ago
POSSIBLE POINTS: 2
serious [3.7K]

Answer:  max capacity is 1625 gallons.

Diagram is shown below.

=========================================================

Explanation:

We'll draw two horizontal number lines to help make a comparison or connection between percentages and tank capacity.

For the top number line, make 5 sections with the labels: 0%, 20%, 40%, 60%, 100%. The reason I'm picking 5 is because 40% = 40/100 = 2/5. So having 40% capacity means we're 2/5 full. That denominator 5 tells us how to subdivide each number line.

The bottom number line will also have 5 sections. We only know one label for this bottom portion right now. That label is 650. Place this directly under the "40%". This visually is one way to represent that 650 gallons is 40% filled. See the diagram below.

Cut the 650 in half to get 325. This corresponds to 40% cut in half to get 20%. Therefore, 325 will go under the 20%. Being 20% full means we have 325 gallons of water.

To figure out the 60% portion, we will multiply 325 by 3. This is because 3*20% = 60%, so 3*325 = 975. We'll write "975 gallons" under the "60%"

Then we have 1300 gallons under the 80% since 4*325 = 1300. Note how 4*20% = 80%, so that's where the '4' multiplier comes from.

Finally, we multiply 325 by 5 to get 1625 and that represents the full tank's capacity. Technically we could have just jumped to this directly without having to find the 60% or 80% capacity values, but it's good practice I think.

Again the diagram is shown below. The answer we're after is at the very bottom right corner. It's under the 100% to indicate the tank is completely full, or has reached max capacity.

-----------------------

Here's a way to find the answer without a double number line. This method involves setting up a proportion.

(40% full)/(650 gallons) = (100% full)/(x gallons)

40/650 = 100/x

40x = 650*100

40x = 65000

x = 65000/40

x = 1625

We confirm that the tank's max capacity is 1625 gallons.

4 0
2 years ago
a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
4 cot theta<br>=<br>tan theta<br>how do I I find the value of quadrant?​
Ray Of Light [21]

Answer:

4cotα=tanα

4(1/tanα)=tanα

(4/tanα)=tanα

cross multiply

=> 4=tan²α

√4=√tan²α

±2=tanα

α=arc( tan) |2|

α=63.4° ( in first quadrant)

and

α=180+63.4=243.4 in the third quadrant

since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)

α=180–63.4=116.6° in the second quadrant

α=360–63.4=296.6 in the fourth quadrant

therefore theta( in my case, alpha) lies in all four quadrants and is equal to:

α=63.4°,243.4°,116.6°and 296.6°

5 0
3 years ago
F(x)=x+ 5<br> g(x) = x-4
TiliK225 [7]
-5 is for f(x)=x+5
4 is for g(x)=x-4
Hope this helps!!
4 0
3 years ago
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