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2 years ago

How to find the first n terms of a quadratic sequence a1 = 3, r = 2, n =5

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

3 0

We suspect you mean "geometric sequence". Multiply each term by r to get the next.

a1 = 3 . . . . . given

a2 = 3*2 = 6

a3 = 6*2 = 12

a4 = 12*2 = 24

a5 = 24*2 = 48

_____

A quadratic sequence is one in which second-differences are a constant. You have not provided enough information about the sequence so that more terms of a quadratic sequence could be found. While you may occasionally see problems asking you to write the formula for one of these, they are rarely studied in any detail in Algebra. At least three terms are needed before the next terms can be predicted.

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Olenka [21]

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3 years ago

What is the first step in solving the equation? +4= -2

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Step-by-step explanation:

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2 years ago

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alisha [4.7K]

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Step-by-step explanation:

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3 years ago

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

Step 1:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

step 2:-

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

verification:-

$AC^2 = AB^2 + BC^2$

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

3 years ago

Read 2 more answers

Help please asap algebra 2

timurjin [86]

X = approximately 633

Steps:
lnx + ln3x = 14

ln3x^2 = 14 : Use the log property of addition which is to multiply same log together so you multiply x and 3x because they have log in common

(ln3x^2) = (14) : take base of e on both sides to get rid of the log
e e

3x^2 = e^14 : e cancels out log on the left side and the right side is e^14

x^2 = e^14 / 3 : divide both sides by 3

√x^2 = √(e^14 / 3) : take square root on both sides to get rid of the square 2 on x

x = √(e^14) / √3 : square root cancels out square 2 leaving x by itself

x = e^7 / √3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7

x = 633.141449221 : solve

4 0

2 years ago