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marissa [1.9K]
3 years ago
7

How to find the first n terms of a quadratic sequence a1 = 3, r = 2, n =5

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0

We suspect you mean "geometric sequence". Multiply each term by r to get the next.

a1 = 3 . . . . . given

a2 = 3*2 = 6

a3 = 6*2 = 12

a4 = 12*2 = 24

a5 = 24*2 = 48

_____

A <em>quadratic</em> sequence is one in which second-differences are a constant. You have not provided enough information about the sequence so that more terms of a quadratic sequence could be found. While you may occasionally see problems asking you to write the formula for one of these, they are rarely studied in any detail in Algebra. At least three terms are needed before the next terms can be predicted.

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A counting number is a multiple of 13 and is also divisible by 4 and 6. What is the smallest number that satisfies these conditi
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8 0
3 years ago
Find the slope of the line that is parallel and perpendicular <br><br> -7x-2y=4
Rus_ich [418]

\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{7}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{7}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{7}}}

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5 0
3 years ago
Find the area of the shaded sector of the circle. Leave your answer in terms of pi.
pentagon [3]
We know that
area  of circle =pi*r²
for r=4 ft
area=pi*4²------> 16*pi ft²

<span>the shaded sector of the circle represent 3/4 of the total area
so
3/4*16*pi-----> 12*pi ft</span>²

the answer is
 12*pi ft²
3 0
3 years ago
Read 2 more answers
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