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2 years ago

How to find the first n terms of a quadratic sequence a1 = 3, r = 2, n =5

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

3 0

We suspect you mean "geometric sequence". Multiply each term by r to get the next.

a1 = 3 . . . . . given

a2 = 3*2 = 6

a3 = 6*2 = 12

a4 = 12*2 = 24

a5 = 24*2 = 48

_____

A quadratic sequence is one in which second-differences are a constant. You have not provided enough information about the sequence so that more terms of a quadratic sequence could be found. While you may occasionally see problems asking you to write the formula for one of these, they are rarely studied in any detail in Algebra. At least three terms are needed before the next terms can be predicted.

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Answer:

a) n =1623

b) $ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208$

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken

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Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by $\alpha=1-0.96=0.04$ and $\alpha/2 =0.02$ . And the critical value would be given by: