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marissa [1.9K]
3 years ago
7

How to find the first n terms of a quadratic sequence a1 = 3, r = 2, n =5

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0

We suspect you mean "geometric sequence". Multiply each term by r to get the next.

a1 = 3 . . . . . given

a2 = 3*2 = 6

a3 = 6*2 = 12

a4 = 12*2 = 24

a5 = 24*2 = 48

_____

A <em>quadratic</em> sequence is one in which second-differences are a constant. You have not provided enough information about the sequence so that more terms of a quadratic sequence could be found. While you may occasionally see problems asking you to write the formula for one of these, they are rarely studied in any detail in Algebra. At least three terms are needed before the next terms can be predicted.

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Tonya and Pearl each completed a separate proof to show that alternate interior angles AKL and FLK are congruent. Who completed
zalisa [80]

Answer:

Tonya proof is correct
and Pearl proof is wrong

Step-by-step explanation:

AKL and GKB are obviously congruent. But the reasons given are different, One of the justification is Vertical Angles Theorem, and the other is Adjacent Angles.

But the correct justification is the Vertical Angles Theorem, because the angles are Vertically away from each other, or the angles are at opposite sides of each other. Which is when Vertical Angles Theorem is applied.
Making Tonya correct since that was the answer he given.

The definition of Adjacent Angles is incorrect, this Theorem is used when the angles are Adjacent to each other. When the angles are on the same line as the other angle, is when the definition of Adjacent Angles is applied. Not in this situation

8 0
2 years ago
The equation of a parabola is y=x2+6x+9. Write the equation in vertex form.
nignag [31]

Answer:

Step-by-step explanation:

Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

x^2+6x=-9

Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

x^2+6x+9=-9+9

The reason we do this is to create a perfect square binomial on the left:

(x+3)^2=0 (obviously the 0 results from the addition of 9 and -9). Move the 0 back over to the other side and set the quadratic back equal to y:

(x+3)^2+0=y

This gives you a vertex of (-3, 0), which is a minimum value, since the parabola opens upwards.

6 0
3 years ago
Simplify fully: √18 / √8
sukhopar [10]
Sqrt18  = 3 sqrt2
sqrt 8 = 2 sqrt2

sqrt18 / sqrt 8  = 3 sqrt2 / 2 sqrt2  = 3/2  answer
4 0
3 years ago
Read 2 more answers
How to do questions C and E ? Please help !!! <br> Thank You :)
mestny [16]
It is the right answer.
6 0
4 years ago
The slant asymptote of f(x)=x^2-4x+1/2x-3 is y=1/2x-5/4 <br> t or f
sveta [45]

Answer:

True

Step-by-step explanation:

Given that a function is

f(x)=\frac{x^2-4x+1}{2x-3}

We are to find the slant asymptote if any for this function

Since numerator is of degree 2 and denominator 1, let us divide and then check

Doing long division we find

f(x)=\frac{1}{2} [x-\frac{5}{2} ]-\frac{11}{4(2x-3)}

Thus we find the asymptote y= the quotient obtained i.e

\frac{1}{2} [x-\frac{5}{2} ]\\=\frac{x}{2} -\frac{5}{4}

Hence asymptote is

y=1/2x-5/4

Statement given is true.

4 0
3 years ago
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