Answer:
The best answer to the question: The preferential use of phosphatidylinositol and phosphatidylethanolamine in the cytoplasmic leaflet of membranes leads to increased:___ would be, D: All of the answers are correct.
Explanation:
There is still a lot of debate among scientists as to the exact way in which phospholipids are distributed between the two leaflets of a cell´s plasma membrane, but what they do know is that there are four kinds, and that phosphatidylinositol (a sterol) and phosphatidylethanolamine appear most commonly on the cytosolic, or cytoplasmic side of the membrane. They also believe that it is this particular arrangement which allows the cytoplasmic side of the membrane to be slightly negatively charged and this role will play a major part in a membrane´s ability to generate an action potential. Also, it is known that these negatively charged ends of the bilayer will allow certain proteins, positively charged ones, to be inserted, and connected to it, to become transporters, or mediators in action potentials and normal activities of cells. Finally, since fatty acids and cholesterol are associated with phospholipids, but have a tendency to be attracted to these particular two types, they tend to give the overall structure fluidity, but also permit the inner leaflet to assume its particular circular shape around the cytoplasm. This is why the answer is D.
Answer: C. Your new organism at a succulent mouse who was nibbling on some grass.
A food chain can be defined as a linear sequence in which one organism is consumed by another organism so as to sustain it's life. A primary consumer can be defined as the organism which is typically a herbivore which feeds upon the primary producers like plants and other autotrophs.
According to the situation given, a succulent mouse can be considered as primary consumer who was nibbling on some grass.
Answer:They get there energy by autotrophs
Explanation:
They get there energy by autotrophs
Answer:
Explanation:
using the formula p² + 2pq + 2pr + q²+ 2qr + r² = 1 where p is IA allele is 0.35 and q is IB allele is 0.15.
Thus, the expected frequency of people with type AB blood in this population will be (2pq) = 2 x 0.35 x 0.15 = 0.105
b. The expected frequency of people with type A blood will be p² + 2pr = where r is found using the formular p + q + r = 1 = 1 - (p+q) = 1 - (0.35+0.15) = 0.5
Thus, we have the expected frequency of people with type A blood to be (0.35² + 2x0.35x0.5) = 0.4725.
c. <u> p² + 2pr</u> + <u>2pq </u>+ <u>q² + 2qr</u> +<u> r²</u>
AA AO AB BB BO OO
1850 180 635 2335
frequency of IA- p = (1850 + 180/2) / 5000 = 0.388
frequency of IB- q = (635 + 180/2) / 5000 = 0.145
frequency of i- r = 2335/ 5000 = 0.467.
since r² = 2335, r = √2335 = 48.32
using the formula p + q + r = 1
Answer:
Liza was unprepared for menarche; her mother hadn't even told her about it yet.
Explanation:
The body of the teenagers undergoes through the different physical and physiological change. Both girls and boys becomes reproductively mature and has changed in the voice and development of special physical characters.
The girls starts shows menstruation. The start of the menstruation is known as menarche. The girls should give prior knowledge and support during this stage. In case of Liza, she was unprepared for the menarche and has no prior knowledge. The Liza's mother did not give her any knowledge.
Thus, the correct answer is option (a).
