Answer:
Statement C is the only one that is necessarily true for exons 2 and 3. It is also true for exons 7 and 8. While statements A and B could be true, they don’thave to be. Because the protein sequence is the same in segments of the mRNA that correspond to exons 1 and 10, neither choice of alternative exons (2 versus 3, or 7 versus 8) can alter the reading frame. To maintain the normal reading frame—whatever that is—the alternative exons must have a number of nucleotides that when divided by 3 (the number of nucleotides in a codon) give the same remainder. Since the sequence of the a-tropomyosin gene is known, it is possible to check to see the actual state of affairs. Exons 2 and 3 both contain the same number of nucleotides, 126, which is divisible by 3 with no remainder.
Compounds that do not contain carbon
The first thing that the nurse should do is TO START CHEST COMPRESSION.
Cardiopulmonary arrest refers to a sudden loss of blood flow, which occur as a result of the failure of the heart to actively pump blood. Performing chest compress on a victim of cardiopulmonary attack will help to restore the pumping function of the heart again.
Answer: Option E) None of the above is true; this enzyme could bind none of these.
Explanation:
Lactose is a dissacharide composed of glucose and galactose. Hence, the enzyme lactase break down lactose into its simple sugar constituents.
However, lactase cannot bind nor break down amino acids, starch (with only glucose units) or sucrose (with two glucose units) because their constituent molecules differ markedly from that of lactose.
Thus, the enzyme lactase could bind with none of the options provided except lactose
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