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bulgar [2K]
3 years ago
10

Betsy is shopping for a new rug, and she finds a square rug that she wants to purchase for her living room. Before purchasing th

e rug, she needs to know the side measure. She knows that the area of the rug is A square feet.
Which of the following functions would best model the situation above?
A.) square root
B.) exponential
C.) absolute value
D.) cube root
Mathematics
2 answers:
disa [49]3 years ago
6 0
The answer is A: square root.

If she knows the area is x feet squared, then you have to find the square root of the number, to find the side length. Hope that helps!

Georgia [21]3 years ago
3 0
<h2>Answer:</h2>

A. square root is the right answer.

Step-by-step explanation:

Now we know that, Betsy finds a <u>square rug</u> that she wants to purchase for her living room and she needs to know the side measure.

Area of the rug is A square feet.

To model this situation, square root function is the best.

We know that area of square having side 's' = s\times s=s^{2}

A = s^{2}

So, s=\sqrt{A}

Lets take an example.

Let the area of the rug be 25 square feet.

So, side will be : side \times side = 25

side =\sqrt{25}

side = 5 feet

Hence, the answer is square root function.

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Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

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Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

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