$(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5$

$\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5$

5 0

3 years ago

You know that 5^2=25. How can you use this fact to evaluate 5^4

PIT_PIT [208]

Answer:

5^4 = 625

Step-by-step explanation:

5^4 is just 25 times 25

7 0

3 years ago

Select the correct answer.<br> Which statement is true?

dusya [7]

Answer:

third option is the correct

Step-by-step explanation:

A function is "odd" when f (-x) = - f (x) for all x. ... For example, functions like

f (x) = x3,
f (x) = x5,
f (x) = x7, ... are odd functions.

6 0

2 years ago

Read 2 more answers

Round the number to the hundredths place. 26,379.87492

Ivahew [28]

If you look at the numbers past the decimal point, the first digit - 8 - is in the tenths place. So, - 7 - is in the hundredths. What number is beside that? 4. When you round four, does it go up to ten or down to zero? Which is it closer to? The answer is zero.

So, the 7 in the hundredths place stays the same and any numbers after it are turned to zeros and cut off. Ending up with 26,379.87

8 0

3 years ago