Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
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Answer:
The Update statement in the DML is used for changing existing data in a table.
Explanation:
Their are following Sql statement in the DML.
Insert
This SQL statement is used for inserting data into the table.
select
This SQL statement is used for retrieving data from database
update
This SQL statement is used for updating data in a table.
delete
This SQL statement is used for delete data from database .
The "UPDATE" SQL statement in DML is used for Modify the data in the existing table .
Following are the syntax of Update SQL query
Update tablename
set column1=value1,column2=value2............column N=valueN
Where condition;
Example :Suppose we have student table and (rollno,name,age and add) are the field for that table we have to change the address of rollno 105
Then we use update query like that
UPDATE STUDENT
SET add='kalam nagar'
where rollno=105;
Answer:
A fixed expense is an expense that has a constant total expense value (the total amount of the fixed expense) that remains the same (does not change) when there is a change in the number being managed, manufactured, or sold
Examples of fixed expense includes; depreciation of assets, salaries of workers, payment for rental lease, and some utility payment, such as road users toll fees payment at a toll gate
Explanation:
let's say they catch-up to each other after t hour.
so
in t hour distance travelled by Renee
d = speed × time = 50t
in t hour distance travelled by Kim
d = speed × time = 60(t-1) + 0×1 = 60(t-1)
Note: here kim didn't covered any distance in first hour and in rest t-1 hour it travelled all distance
now.as distance travelled by both is same so
60(t-1) = 50t
60t -60 = 50t
adding 60 both sides
60t = 50t+60
subtracting 50t both sides
60t -50t = 50t+60 - 50t
10t = 60
dividing by 10 both sides
t = 60/10 = 6
so in 6 hour both will catch-up to each other
