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3 years ago

What 1 7/8 × 2 3/8 will be equal to,greater than or less than 2 3/8

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

5 0

Answer:

greater than

Step-by-step explanation:

Since 2 $\frac{3}{8}$ is being multiplied by a number greater than 1, the result will be greater than 2 $\frac{3}{8}$

If the multiplier was 1 then the result would be equal to 2 $\frac{3}{8}$

If the multiplier was between 0 and 1 the result would be less than 2 $\frac{3}{8}$

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15+9=?(5+3) please help

Tema [17]

Answer:

because 15 + 9 = 24

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= 24 = 24

Step-by-step explanation:

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3 years ago

Write the equation in standard form for the circle that has a diameter with endpoints (- 1, 12) and (- 1, 8)

matrenka [14]

Answer:

The equation in standard form is $(x + 1)^{2} + (y - 10)^{2} = 4$

Step-by-step explanation:

The distance from (-1, 12) to (-1, 8) = 4 = diameter of the circle. So, 2 = radius

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3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

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